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Anju 9 posts 29 karma points

Feb 03, 2012 @ 09:32

0

XSLT open in new window

Hi,

I would like to open link in a new window.I have attached the XSLT code below.

I would like to open only

<xsl:when test="pText!=''">
  <xsl:value-of select="pText" />
</xsl:when>

in new window.

Pls help me ASAP.

<a >
<xsl:attribute name ="href">
<xsl:choose>
<xsl:when test="pText!=''">
  <xsl:value-of select="pText" />
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="umbraco.library:NiceUrl(pLink)" />
</xsl:otherwise>
</xsl:choose>
</xsl:attribute>
<img src="{uploadPhoto}"  alt="{@nodeName}"/>
  </a>

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Chriztian Steinmeier 2800 posts 8791 karma points MVP 8x admin c-trib

Feb 03, 2012 @ 09:45

Hi Anju,

You can do that like this:

<a href="{umbraco.library:NiceUrl(pLink)}">
    <xsl:if test="normalize-space(pText)">
        <!-- Override the href attribute -->
        <xsl:attribute name="href">
            <xsl:value-of select="pText" />
        </xsl:attribute>
        <!-- Add a target attribute -->
        <xsl:attribute name="target">_blank</xsl:attribute>
    </xsl:if>
    <img src="{uploadPhoto}" alt="{@nodeName}" />
</a>

/Chriztian

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Anju 9 posts 29 karma points

Feb 03, 2012 @ 10:26

0

Can I able to do like this? But now it is not redirecting.

<xsl:when test="pText!=''">
<a target="_blank">
<xsl:attribute name="href">
<xsl:value-of select="pText" />
</xsl:attribute>
</a>
</xsl:when>

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