pass strongly type model in razor view

David Dupont 61 posts 115 karma points

Nov 29, 2012 @ 20:32

Pass strongly type model in razor view

Hi everyone,

I'm trying to implement strongly type model in controller using Umbraco 4.10 and I can't figure what I'm doing wrong.

Here is my razor view:

@model Umbraco.Web.Mvc.UmbracoViewPage<Emakina.Umbraco.DocumentTypes.TextPage>
@{
    this.Layout = "SiteRoot.cshtml";
}

And here is my custom controller :

    public class TextPageController : RenderMvcController
    {
        public override ActionResult Index(RenderModel model)
        {
            //we will create a custom model
            var customModel = ContentHelper.GetCurrentContent() as TextPage;

            //Example for 4.10:

            //get the template name from the route values:
            var template = ControllerContext.RouteData.Values["action"].ToString();
            //return an empty content result if the template doesn't physically 
            //exist on the file system
            if (!EnsurePhsyicalViewExists(template))
            {
                return Content("");
            }
            //return the current template with an instance of MyCustomModel
            return View(template, customModel);
        }
    }

When I call the page I get this ysod and I wonder why since the model returned in controller is TextPage and the model declared in razor view is TextPage.

Thanks per advance.

DDU

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David Dupont 61 posts 115 karma points

Nov 29, 2012 @ 20:57

Here is the error :

[InvalidOperationException: The model item passed into the dictionary is of type 'Emakina.Umbraco.DocumentTypes.TextPage', but this dictionary requires a model item of type 'Umbraco.Web.Mvc.UmbracoViewPage`1[Emakina.Umbraco.DocumentTypes.TextPage]'.]
   System.Web.Mvc.ViewDataDictionary`1.SetModel(Object value) +403
   System.Web.Mvc.ViewDataDictionary..ctor(ViewDataDictionary dictionary) +708
   System.Web.Mvc.WebViewPage`1.SetViewData(ViewDataDictionary viewData) +74
   System.Web.Mvc.RazorView.RenderView(ViewContext viewContext, TextWriter writer, Object instance) +139
   System.Web.Mvc.ViewResultBase.ExecuteResult(ControllerContext context) +384
   System.Web.Mvc.<>c__DisplayClass1c.<InvokeActionResultWithFilters>b__19() +33
   System.Web.Mvc.ControllerActionInvoker.InvokeActionResultFilter(IResultFilter filter, ResultExecutingContext preContext, Func`1 continuation) +818804
   System.Web.Mvc.ControllerActionInvoker.InvokeActionResultWithFilters(ControllerContext controllerContext, IList`1 filters, ActionResult actionResult) +265
   System.Web.Mvc.ControllerActionInvoker.InvokeAction(ControllerContext controllerContext, String actionName) +818320
   System.Web.Mvc.Controller.ExecuteCore() +159
   System.Web.Mvc.ControllerBase.Execute(RequestContext requestContext) +335
   System.Web.Mvc.<>c__DisplayClassb.<BeginProcessRequest>b__5() +62
   System.Web.Mvc.Async.<>c__DisplayClass1.<MakeVoidDelegate>b__0() +20
   System.Web.Mvc.<>c__DisplayClasse.<EndProcessRequest>b__d() +54
   System.Web.CallHandlerExecutionStep.System.Web.HttpApplication.IExecutionStep.Execute() +469
   System.Web.HttpApplication.ExecuteStep(IExecutionStep step, Boolean& completedSynchronously) +375

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David Dupont 61 posts 115 karma points

Nov 29, 2012 @ 21:14

Forget about it, the following line was the culprit :

this.Layout="SiteRoot.cshtml";

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Edwin van Koppen 156 posts 270 karma points

Dec 04, 2012 @ 16:44

You give the wrong object back, i stopped using the index to override and use my own controller like this

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.Mvc;
using Umbraco.Web.Models;
using Umbraco.Web.Mvc;
using umbraco.cms.businesslogic.template;
using ViewModel;

namespace W3S.Controllers
{
    public class HomeController : W3S.Models.Master
    {
        public ActionResult Home(RenderModel Model) {
            HomeViewModel HVM = new HomeViewModel();
            HVM.UmbracoModel = Model;

            return View(HVM);
        }


    }

}
namespace ViewModel {
    public class HomeViewModel {
        public RenderModel UmbracoModel { get; set; }
    }
}

@model ViewModel.HomeViewModel
@{
ViewBag.Title = "Test";
Layout = "~/Views/Shared/_Layout.cshtml";
}

<h2>@Model.UmbracoModel.Content.GetProperty("titel").Value</h2>
<div>@Html.Raw((string)Model.UmbracoModel.Content.GetProperty("body").Value)</div>

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Edwin van Koppen 156 posts 270 karma points

Dec 05, 2012 @ 08:51

I'm busy with the same problem but i stumbled upon this one http://our.umbraco.org/forum/core/general/36526-U411-Looks-like-NodeUrl-functionality-is-broken?p=0

So strong typed objects you cannot get a url... pretty big problem for me.

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Pass strongly type model in razor view