finding parent node by alias using umbraco 6 - API Questions

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maanehunden 61 posts 105 karma points

Aug 15, 2013 @ 10:18

Finding Parent Node By Alias using Umbraco 6 ?

Hi All

What is your opinion on the following code, i have to find parent of a specific type. I Know that "Document" is deprecated, so what is the best way of doing this with "Content".

thanks.. Maanehunden

    public static Document FindParentNodeByAlias(this Document current, string alias)
    {
        Document found = current;
        while (found.Id != -1)
        {
            found = new Document(found.ParentId);
            if (found.ContentType.Alias == alias)
            {
                break;
            }
        }

        return found;
    }

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João Ferreira 19 posts 40 karma points

Aug 15, 2013 @ 10:55

0

Hi, I usually use this method to find it:

public static DynamicNode GetParentByNodeType(DynamicNode node, string parentNodeType)
{
DynamicNode parent = node;
for (int i = 0; i < node.Level; i++)
{
if (parent.NodeTypeAlias == parentNodeType)
{
break;
}

parent = parent.Parent;
}

return parent;
}

I hope that helps. Also about getting a parent I have this ones in my helper:

public static Document GetParentByLevel(Document node, int level)
{
CMSNode p = new CMSNode(node.Id);
for (int i = 0; i < node.Level; i++)
{
if (p.Level == level)
{
break;
}
p = p.Parent;
}

return new Document(p.Id);
}

public static List<string> GetAllParentToLevel(DynamicNode node, int level)
{
DynamicNode parent = node;
List<string> parents = new List<string>();
for (int i = 0; i < node.Level; i++)
{
if (parent.Level == level)
{
break;
}
parents.Add(parent.Id.ToString());
parent = parent.Parent;
}

return parents;
}

You can use either Document or DynamicNodes.

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Dave Woestenborghs 3504 posts 12135 karma points MVP 9x admin c-trib

Aug 15, 2013 @ 10:58
100
The document api was meant for creating/updating content. If you are using v6 have a look at the contentservice API (http://our.umbraco.org/documentation/reference/Management-v6/Services/ContentService)

For querying content to use on the frontend you should use the Node API (v4) or TypedContent(V6). As a alternative you could use uQuery.

You can find some documentation here : http://our.umbraco.org/documentation/Reference/Querying/uQuery/Content/Nodes (v4 and v6)

http://our.umbraco.org/documentation/reference/Mvc/querying (v6 only)

So you would be looking for something like this :
```
Node homeNode = uQuery.GetCurrentNode().GetAncestorNodes().Where(x => x.NodeTypeAlias == "home").FirstOrDefault();
```
This would result in the first ancestor node with node type alias "home"

Dave
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maanehunden 61 posts 105 karma points

Aug 15, 2013 @ 12:01

0

Thanx for your replies Dave and João.

uQuery is clearly the way (c:

/Maanehunden

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andrew shearer 512 posts 661 karma points

Aug 16, 2013 @ 04:06

0

uQuery is not the way! uQuery doesn't use the new library that was introduced in umbraco 6. It uses the old libraries from 4.

@maanehunden - where are you trying to use this method, a view? if so, you should be able to use:

Model.Content.AncestorOrSelf("yourAliasHere")

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maanehunden 61 posts 105 karma points

Aug 16, 2013 @ 08:51

0

Tnx for the reply Andrew.

I am working on a custom datatype for the backoffice, so i can't use Model.Conten ): the Node is not populated so i am forced to use Document, because it works.

any other suggestions ?

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andrew shearer 512 posts 661 karma points

Aug 16, 2013 @ 09:07

0

Document is now known in the umb6 API as "Content":

http://our.umbraco.org/documentation/reference/Management-v6/Models/Content

although, that page says not to use it for "complex queries" as it might not be fast enough, so I'm not sure what the Umbraco team suggest instead :(

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