When you say you cannot get it to work?  What is the problem?  Charlie :)

In my partial view if I try and get the next sibling using this code it gives a The name 'CurrentPage' does not exist in the current context error.

var test = CurrentPage.Next();

Trying it this way gives,  'Racing.CheckoutModel' does not contain a definition for 'Content' and no extension method 'Content' accepting a first argument of type 'Racing.CheckoutModel' could be found (are you missing a using directive or an assembly reference?)

var test2 = Model.Content.Next();

Umbraco.Web.Mvc.UmbracoViewPage

Thats because of this statement and i am not sure how to fix it.

Try using Umbraco.Web.Mvc.UmbracoViewPage

and dont use any of the model properties, just to assert this is the case. Charlie :)

You could let your custom model inherit from RenderModel (which Umbraco uses everywhere): http://our.umbraco.org/forum/templating/templates-and-document-types/38311-Using-RenderMvcController?p=2#comment153025

So you have your own model with it's own properties, but Model.Content will also work.

Jeroen

Jeroen, this sounds like a great solution. Can you just call Model...... ect ect from your own model?

If the context is null will this throw? Charlie :)

Setting my CheckoutModel to inherit from RenderModel allows me to get the sibling using Model.Content however I get this exception when posting my form.

No parameterless constructor defined for this object.

When I give CheckoutModel a parameterless constructor it moans that RenderModel doesn't have a constructor that doesn't allow it.

I don't see how to pass the currentpage to my model during the post however.

Try this :-) http://our.umbraco.org/forum/templating/templates-and-document-types/38311-Using-RenderMvcController?p=2#comment155535

Jeroen

Note to self, scroll through threads in case there is anything else pertinent ;)

Thanks Jeroen

Doh just marked the wong post as solution ;)

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