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  • Anton Oosthuizen 206 posts 486 karma points
    Sep 23, 2013 @ 13:30
    Anton Oosthuizen
    0

    6.1.5 Returning Partial View as string to JSON

    Hi All

    I need some help here.

    I need to return a partial view as a string for JSON How would I go about this. Please note that my view inherits from a DynamicNode

    Code:

       public JsonResult HandleAddReview(ReviewModel Model)
    {
        DynamicNode dn = new DynamicNode(venuecontent.Id);
        return Json(new {val =   PartialView("[Members]Reviews",dn)});
    }
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  • Alex Skrypnyk 6163 posts 24143 karma points MVP 8x admin c-trib
    Sep 23, 2013 @ 15:26
    Alex Skrypnyk
    100

    Hi Anton,

    You have to do some method which will render Partial view in string.

    return Json(new { htmlData = RenderRazorViewToString("partialView Path", model, ControllerContext, ViewData, TempData) }, JsonRequestBehavior.AllowGet);


    public static string RenderRazorViewToString(string viewName, object model, ControllerContext controllerContext, ViewDataDictionary viewData, TempDataDictionary tempData)
    {
        viewData.Model = model;
        using (var sw = new StringWriter())
        {
            var viewResult = ViewEngines.Engines.FindPartialView(controllerContext, viewName);
            var viewContext = new ViewContext(controllerContext, viewResult.View, viewData, tempData, sw);
            viewResult.View.Render(viewContext, sw);
            viewResult.ViewEngine.ReleaseView(controllerContext, viewResult.View);
            return sw.GetStringBuilder().ToString();
        }
    }

    Thanks, Alex

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  • Anton Oosthuizen 206 posts 486 karma points
    Sep 25, 2013 @ 11:11
    Anton Oosthuizen
    0

    Shot Alex.

    That is exactly what I needed.

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