This is more of a WEB.API question than Umbraco, but here goes:
I have created a simple UmbracoApiController like this:
public class LicenseController : UmbracoApiController
{
public IList<WaterwayLicense> GetAll()
{
var service = new LicenseService();
var result = service.GetWaterwayLicenses();
return result;
}
}
If your WaterwayLicense class is outside of your control, then you would have to do it with a custom view model like this
public List<WaterwayLicenseViewModel> GetAll()
{
var service = new LicenseService();
var result = service.GetWaterwayLicenses();
return result.Select(licence=> new WaterwayLicenseViewModel(){ID = licence.ID, Tittel = licence.Tittel}).ToList();
}
public class WaterwayLicenseViewModel
{
public int ID { get; set; }
public string Tittel { get; set; }
}
Thanks for the reply Stephen. I also managed to solve it by rewriting the method like this:
public HttpResponseMessage GetAll()
{
var service = new LicenseService();
var result = service.GetWaterwayLicenses();
var jsonResult = JsonConvert.SerializeObject(result);
var response = this.Request.CreateResponse(HttpStatusCode.OK);
response.Content = new StringContent(jsonResult, Encoding.UTF8, "application/json");
return response;
}
What method would you prefer when it comes to performance? The JSON serialization has to happen some place, so could I just do it in the code? The list will contain up to 10 000 records so I think first getting the items from the LicenseService then copy it to a new list will add more overhead.
One drawback I see is that it will ruin the option to retrieve the data as XML, but in this case performance has a higher priority.
That would work too, JsonConvert is Newtonsoft's json.net which is usually regarded as the fastest.
if you wanted to support Xml you could do something like this
public HttpResponseMessage GetAll()
{
var service = new LicenseService();
var result = service.GetWaterwayLicenses();
var response = this.Request.CreateResponse(HttpStatusCode.OK);
if (Request.AcceptTypes.Contains("application/json"))
{
var jsonResult = JsonConvert.SerializeObject(result);
response.Content = new StringContent(jsonResult, Encoding.UTF8, "application/json");
}
else if (Request.AcceptTypes.Contains("application/xml"))
{
XmlSerializer xmlSerializer = new XmlSerializer(result.GetType());
using (StringWriter textWriter = new StringWriter())
{
xmlSerializer.Serialize(textWriter, result);
response.Content = new StringContent(textWriter.ToString(), Encoding.UTF8, "application/xml");
}
}
else
{
throw new Exception("Accepted content type not supported.");
}
return response;
}
Although you may want to save the XmlSerializer in a static variable so you don't have to instantiate it every time.
Exclude type parameter from JSON output by UmbracoApiController
This is more of a WEB.API question than Umbraco, but here goes: I have created a simple UmbracoApiController like this:
The output of this becomes like this:
But I really don't need the $type parameters and would like to have it like this:
How can this be achieved?
If your WaterwayLicense class is outside of your control, then you would have to do it with a custom view model like this
Thanks for the reply Stephen. I also managed to solve it by rewriting the method like this:
What method would you prefer when it comes to performance? The JSON serialization has to happen some place, so could I just do it in the code? The list will contain up to 10 000 records so I think first getting the items from the LicenseService then copy it to a new list will add more overhead.
One drawback I see is that it will ruin the option to retrieve the data as XML, but in this case performance has a higher priority.
That would work too, JsonConvert is Newtonsoft's json.net which is usually regarded as the fastest.
if you wanted to support Xml you could do something like this
Although you may want to save the XmlSerializer in a static variable so you don't have to instantiate it every time.
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