Hi John,

Can you show your view ? Can you inherit your views from UmbracoViewPage?

@inherits UmbracoViewPage

It solves problem for me.

Thanks, Alex

Hi Alex I want to inherit my custom Model but retain access to RenderModel properties like @Model.GetPropertyValue("bodyText") etc. The problem for me lies in the model not the view because it suggests that Umbraco.Web.Models.RenderModel doesn not contain a construction that takes 0 arguments.

I'm trying to understand this point in the documentation

@inherits Umbraco.Web.Mvc.UmbracoViewPage<Your Model here>

That should do the trick

Hi John,

As you suspected, there are no parameterless constructors.

The easiest way to achieve what (I think) you want, is to override the Index method in the controller, so:

namespace JEC.Web.Models
{
    public class Product : Umbraco.Web.Models.RenderModel
    {
        public override ActionResult Index(RenderModel renderModel)
        {
            ExampleModel myModel = new ExampeModel();

            // Perform your mappings here (or call a mapper)
            myModel.PageTitle = renderModel.GetPropertyValue<string>("pageTitle");

            // If you really want access to the IPublishedContent in your view, simply add it
            // to your strongly typed model
            myModel.Content = renderModel;

            // Then spit it back to your view
           return myModel;
        }
    }

    public class ExampleModel
    {
        public string PageTitle { get; set; }
        public IPublishedContent Content { get; set; }
    }
}

Now in your view, you simply add the model type, and query it to build up your page.

@model JEC.Web.Models.ExampleModel

 <h1>@Model.PageTitle</h1>
 @* You can also query the IPublishedContent too if you wish *@

 <p>@Model.Content.GetPropertyValue<string>("welcomeMessage")</p>

Hope this helps!

Cheers,

HJR

Thanks Hywel I'll give that a try.

Hi John,

If I could work out how to mark as a solution, I would :)

Glad to have been a help.

Cheers,

Hywel

Hi Hywel,

It didn't work and tried your solution also but as there is a shared layouts page your method doesn't work either :(

public class test : Umbraco.Web.Models.RenderModel
    {
        public int ID { get; set; }
    }



  public override ActionResult Index(test model)
    {
        model.ID = 1;
         return View(model);
    }

Now with an error message no suitable method found to override.

If you want to inherit from RenderModel, you could create a constructor that takes an IPublishedContent and calls the base class constructor. Something like this:

public class Product: Umbraco.Web.Models.RenderModel
{
    public Product(IPublishedContent content)
        :  base(content)
    {
    }
}

That is how I usually do it. Depending on your use case, you may have to instatiate your model manually in your controller:

var model = new Product(CurrentPage);

This seems to work for me, but I am sure there are probably much smarter ways to do this.

Hi Asbjørn, could you provide a more detailed example with controller?

My attempt....

Model

    public class Product: Umbraco.Web.Models.RenderModel
    {
        public Products(IPublishedContent content)
            :  base(content)
        {
        }
       public int ID
    }  

Controller

 public override ActionResult Index(RenderModel model)
        {
            var model2 = new Products(CurrentPage);
  return base.Index(model2);
        }

View

@inherits Umbraco.Web.Mvc.UmbracoViewPage<Products>

@Model.ID

Sorry for not getting back to you sooner.

Your example looks pretty good, except for the controller. If you are doing route hijacking, you would usually just call CurrentTemplate(), like this:

public override ActionResult Index(RenderModel model)
{
    var model2 = new Products(CurrentPage);
    return CurrentTemplate(model2);
}

You can also just call an MVC view in the standard MVC way, if you want to.

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