get member email from ipublishedcontent

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Jeroen Breuer 4908 posts 12265 karma points MVP 5x admin c-trib

Nov 04, 2015 @ 16:55

0

Get member email from IPublishedContent

Hello,

I'm using the Umbraco MemberShipHelper. The helper has 2 methods:

GetCurrentMember() GetCurrentMemberProfileModel()

The first method returns an IPublishedContent. How can I get the email of a member from that? The property is available on the ProfileModel that GetCurrentMemberProfileModel() returns, but I prefer not to use 2 methods to get the current member.

Jeroen

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Kevin Jump 2341 posts 14868 karma points MVP 8x c-trib

Nov 04, 2015 @ 17:02
1
Hi,

I had to write some code to do this a few versions back (v7.2) and then you couldn't get it from the IPublishedContent model.

there is an issue somewhere so i am not sure if it got fixed in later versions - but i ended up making the member dynamic
```
var email member.AsDynamic().Email;
```
bit of a hack but it works.
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Ravi Motha 290 posts 500 karma points MVP 8x c-trib

Nov 04, 2015 @ 17:13
105
Jeroen,

I've used the membership helper in this way and can return any of the properties
```
var memberShipHelper = new Umbraco.Web.Security.MembershipHelper(Umbraco.Web.UmbracoContext.Current);
var myUser = memberShipHelper.GetCurrentMember();
```
@myUser.GetProperty("Email").Value

I'm using a 7.2.x and I've had no problems with it
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Jeroen Breuer 4908 posts 12265 karma points MVP 5x admin c-trib

Nov 04, 2015 @ 18:19

0

Thanks for the tips. Will try myUser.GetProperty("Email").Value. The reason I didn't try it is because email isn't a property set on the member type. When the models builder generated a strongly typed model it also didn't contain an email property.

Jeroen

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Anders Bjerner 487 posts 2989 karma points MVP 8x admin c-trib

Nov 04, 2015 @ 20:24
8
Hi Jeroen,

When you reference a member by IPublishedContent it is really an instance of MemberPublishedContent. If you cast to this type, you will have acces to an email property (as well as other member-only properties):
```
@{

    IPublishedContent content = Umbraco.TypedMember(memberId);

    MemberPublishedContent member = (MemberPublishedContent) content;

    <p>@member.Email</p>

}
```
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Tobbe 81 posts 387 karma points c-trib

Jan 05, 2018 @ 09:14
1
When I try to do this I get this error (using umbraco 7.7.2):
```
Unable to cast object of type 'Umbraco.Web.PublishedContentModels.Member' to type 'Umbraco.Web.PublishedCache.MemberPublishedContent'.
```
Getting the same error if I try to use ApplicationContext.Current.Services.MemberService.GetById(memberId)
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Jeroen Breuer 4908 posts 12265 karma points MVP 5x admin c-trib

Nov 05, 2015 @ 10:38
7
Since I'm using the ModelsBuilder I don't get a MemberPublishedContent back, but the generated model which doesn't have the Email property. I fixed it with this code:
```
public partial class Member
{
    public string Email
    {
        get
        {
            return this.GetPropertyValue<string>("Email");
        }
    }
}
```
Jeroen
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Sean Håkansson 67 posts 193 karma points

Dec 11, 2017 @ 14:14

0

Sorry for the newb question and more than a year later :) But where would I put this? (Not in the auto-generated file I'm guessing)

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Kevin Jump 2341 posts 14868 karma points MVP 8x c-trib

Dec 11, 2017 @ 14:23

1

Hi

You can put this in it's own file in somewhere such as the App_Code folder (you might need to create this).

the generated classes are marked as partial, which means you can create other partial classes with the same name across your project and they are turned into one class as compile/run time.

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Richard Eyres 98 posts 580 karma points

Oct 25, 2016 @ 14:05

1

Thanks Jeroen. This was the exact same situation i found myself in. Your reply just saved me a little time. Thank you.

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Chris 12 posts 84 karma points

Oct 24, 2018 @ 14:39
0
I have found you can get the email dynamically, but not typed:
```
.GetPropertyValue("Email").ToString();
```
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