Hi Kukuwka,

There isn't really possible out of the box, but you could write a helper method to do it.

Take a look at Hendys helper methods for umbraco

http://blog.hendyracher.co.uk/umbraco-helper-class/

He has one for GetNodesByName which you could modify to work with media items.

Many thanks

Matt

I want get media name from Section Media ,but not from umbraco.config.

Something like: Instead function "GetMedia(int itemid)" to use "GetMedia(string name)" .

Is there such a possibility?

Thanks

Don't know if you figured this out, but I modified some of the code in the uComponents library to do this.

                   public static List<Media> GetMediaByName(string nodeName)
        {
            List<Media> media = new List<Media>();

            XmlDocument xmlDocument = uQuery.GetPublishedXml(uQuery.UmbracoObjectType.Media);
            XPathNavigator xPathNavigator = xmlDocument.CreateNavigator();
            XPathNodeIterator xPathNodeIterator = xPathNavigator.Select("descendant::*[@nodeName='" + nodeName + "']");

            Media mediaItem;
            while (xPathNodeIterator.MoveNext())
            {
                mediaItem = uQuery.GetMedia(xPathNodeIterator.Current.Evaluate("string(@id)").ToString());
                if (mediaItem != null)
                {
                    media.Add(mediaItem);
                }
            }

            return media;
        }

Hope this helps. Better late than never.

-C

Hi Chad,

Yeah, that method should be in the API :) have just added:

public static List<Media> GetMediaByName(string name)
{
    return uQuery.GetMediaByXPath("descendant::*[@nodeName='" + name + "']");
}

Cheers,

Hendy

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