A UNIX timestamp is number of seconds since 1/1/1970 so if you  used the dateAdd method in umbraco:library to add 1250163047 seconds to 1/1/1970 you would get the correct date object returned and you could format as usual.

T

I think you'll need some .net code to make the conversion BEFORE using it in xslt.

http://codeclimber.net.nz/archive/2007/07/10/convert-a-unix-timestamp-to-a-.net-datetime.aspx

static DateTime ConvertFromUnixTimestamp(double timestamp)
{
    DateTime origin = new DateTime(1970, 1, 1, 0, 0, 0, 0);
    return origin.AddSeconds(timestamp);
}


static double ConvertToUnixTimestamp(DateTime date)
{
    DateTime origin = new DateTime(1970, 1, 1, 0, 0, 0, 0);
    TimeSpan diff = date - origin;
    return Math.Floor(diff.TotalSeconds);
}

and here is another one http://www.codeproject.com/KB/cs/timestamp.aspx

>Tommy

OK excellent thanks guys, I will write this as an XSLT extension.

Warren :)

Tim, I tried it but it didn't work.
Does the 1970 date need to be in a different format?

<xsl:value-of select="umbraco.library:FormatDateTime(umbraco.library:DateAdd('1/1/1970','s', date[@uts]),'dd.mm.yy @ H:mm')"/>

Might need to be like this:

1970-01-01T00:00:00

T

Example:

<xsl:value-of="umbraco.library:FormatDateTime(umbraco.library:DateAdd('1970-01-01T00:00:000','s', 1250163047), 'MMMM d, yyyy')" />

Again not tested - just coding off the top of my head!

T

OK Tim did solve it on earlier with the original date format of 01/01/1970 and it was me being dumb with my XPath Selector.
I should have done date/@uts and NOT date[@uts]

<xsl:value-of select="umbraco.library:FormatDateTime(umbraco.library:DateAdd('01/01/1970','s', date/@uts),'dd dddd MMM yy @ H:mm')"/>

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