Hi Adi,

For some reason I couldn't write a comment on the other post, so you will get it here.

Try this one, I get no error when I save this version.

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp "&#x00A0;"> ]>
<xsl:stylesheet 
    version="1.0" 
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
    xmlns:msxml="urn:schemas-microsoft-com:xslt"
    xmlns:umbraco.library="urn:umbraco.library" xmlns:Exslt.ExsltCommon="urn:Exslt.ExsltCommon" xmlns:Exslt.ExsltDatesAndTimes="urn:Exslt.ExsltDatesAndTimes" xmlns:Exslt.ExsltMath="urn:Exslt.ExsltMath" xmlns:Exslt.ExsltRegularExpressions="urn:Exslt.ExsltRegularExpressions" xmlns:Exslt.ExsltStrings="urn:Exslt.ExsltStrings" xmlns:Exslt.ExsltSets="urn:Exslt.ExsltSets" xmlns:Examine="urn:Examine" 
    exclude-result-prefixes="msxml umbraco.library Exslt.ExsltCommon Exslt.ExsltDatesAndTimes Exslt.ExsltMath Exslt.ExsltRegularExpressions Exslt.ExsltStrings Exslt.ExsltSets Examine ">


<xsl:output method="xml" omit-xml-declaration="yes"/>

<xsl:param name="currentPage"/>

<xsl:template match="/">
<xsl:variable name="about" select="umbraco.library:GetXmlNodeById('1067')"/><!-- Here is the NodeId from here you are pulling all the list of about -->

<xsl:variable name="itemsToDisplay" select="10"/> <!-- Number of items to display per page -->
<xsl:variable name="numberOfItems" select="count($about/*[@isDoc][not(umbracoNaviHide =1)])"/>
<xsl:variable name="jump" select="$itemsToDisplay * $pageNumber" />

<!-- Paging -->
<xsl:variable name="pageNumber">
  <xsl:choose>
    <xsl:when test="umbraco.library:RequestQueryString('page') = ''">
      <xsl:value-of select="1"/>
    </xsl:when>
    <xsl:otherwise>
      <xsl:value-of select="umbraco.library:RequestQueryString('page')"/>
    </xsl:otherwise>
  </xsl:choose>
</xsl:variable>        
    
<xsl:template match="/">
<!-- start writing XSLT -->
  <ul>
  <xsl:for-each select="$news/*[@isDoc][not(umbracoNaviHide =1)]">
    <xsl:if test="position() &lt; $jump and position() &gt;= ($jump - $itemsToDisplay)">
       <li><xsl:value-of select="@nodeName"/></li>  
     </xsl:if>   
  </xsl:for-each>
</ul>

  
  <xsl:call-template name="for.loop">
  <xsl:with-param name="i">1</xsl:with-param>
  <xsl:with-param name="count" select="ceiling($numberOfItems div $itemsToDisplay)"></xsl:with-param>
</xsl:call-template>  
  
  
  </xsl:template>
  
    <xsl:template name="for.loop">
                <xsl:param name="i"/>
                <xsl:param name="count"/>
                
                <xsl:if test="$i &lt;=$count">
                        <xsl:if test="$pageNumber!= $i">
                                <a href="?page={$i}#about" ><xsl:value-of select="$i" /></a>
                        </xsl:if>

                        <xsl:if test="$pageNumber = $i">
                          <a  class="selected"><xsl:value-of select="$i"/></a>
                        </xsl:if>

                        <xsl:call-template name="for.loop">
                                <xsl:with-param name="i" select="$i + 1" />
                                <xsl:with-param name="count" select="$count">
                                </xsl:with-param>
                        </xsl:call-template>
                </xsl:if>
</xsl:template>
</xsl:template>

</xsl:stylesheet>

Hope it will work for you too.

/Dennis

Hi Weird i get the same issue and cant reply on the other threat. :)

Anyways sorry was my mistake where i commented the first part of the variable.

<xsl:variablename="about"select="umbraco.library:GetXmlNodeById('1067')"/><!-- Here is the NodeId from here you are pulling all the list of about -->

instead of 

<xsl:variablename="about"select="umbraco.library:GetXmlNodeById('1067')"/><!-- Here is the NodeId from here you are pulling all the list of about -- >

@Dennis however the loop here should be $about but its on mine again!

<ul>
  <xsl:for-eachselect="$about/*[@isDoc][not(umbracoNaviHide =1)]">
    <xsl:iftest="position() &lt; $jump and position() &gt;= ($jump - $itemsToDisplay)">
       <li><xsl:value-ofselect="@nodeName"/></li>  
     </xsl:if>   
  </xsl:for-each>
</ul>

It should get you working now, i have just tried the code myself.

You can also add a Next or Previous Page url to your paging.

 <xsl:if test="$pageNumber &gt; 1">
<a href="?page={$pageNumber -1}#about" >Previous</a>
</xsl:if>

  <xsl:call-template name="for.loop">
<xsl:with-param name="i">1</xsl:with-param>
<xsl:with-param name="count" select="ceiling($numberOfItems div $itemsToDisplay)"></xsl:with-param>
</xsl:call-template>  

<xsl:if test="(($pageNumber) * $itemsToDisplay) &lt; ($numberOfItems)">
<a href="?page={$pageNumber+1}#about">Next;</a>
</xsl:if>

//Fuji

Hi Dennis,

I have used code you suggested from last post on this thread but unforunately I get this error

I don't understand why only on my website pageNumber isn't defined and or your exapmle it is working fine.. What am I doing wrong?

Best regards, Adi

Hello Fuji,

thank you for promt reply and fast switching to this topic, I really appreciate it.

I will try you suggestion as soon as find out why I see error which I have described in post above.

All the best, Adi

Hello Fuji,

yes, you were riht, I noticed the changes you made in your code and now I understand what was the (simple) issue;(

However, I have good news, code is working but I will have to make some adjustments in order to achieve what I really need on my template.

This is the code which shows active articles on every Textpage of my template.

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp "&#x00A0;"> ]>
<xsl:stylesheet 
  version="1.0" 
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
  xmlns:msxml="urn:schemas-microsoft-com:xslt" 
  xmlns:umbraco.library="urn:umbraco.library"
  exclude-result-prefixes="msxml umbraco.library">

<xsl:output method="xml" omit-xml-declaration="yes"/>

<xsl:param name="currentPage"/>

<xsl:template match="/">

  <xsl:variable name="items" select="$currentPage/ancestor-or-self::* [@isDoc and @level = 2]/* [@isDoc and string(umbracoNaviHide) != '1']"/>

<!-- The fun starts here -->

<xsl:if test="count($items) &gt; 0">
<ul>
<xsl:for-each select="$items">
  <li>
    <a href="{umbraco.library:NiceUrl(@id)}">
      <xsl:value-of select="@nodeName"/>
    </a>
  </li>
</xsl:for-each>
</ul>
    </xsl:if>

</xsl:template>

</xsl:stylesheet>

I use Textapges all the time. Is it possible to simply update this code with code you suggested? This would be almost perfect solution for my template..

All the best, Adi

Hi Adi,

If you want to display only doc with a specific DocType then try something

 <xsl:variable name="items" select="$currentPage/ancestor-or-self::* [@isDoc][@level = 2][not(umbracoNaviHide =1)][self::Textapges ]" />

Hope this is what you are trying to achieve here.

//fuji

Hi Adi There is another option if you are using Razor Views. The code below is pasted from the "Articles" template in the Standard Website Starter Kit (MVC version) and seems to work ok for me on v 6.

@inherits Umbraco.Web.Mvc.UmbracoTemplatePage
@{
    Layout = "SW_Master.cshtml";
    int pageSize = 2; // How many items per page
    int page; // The page we are viewing

    /* Set up parameters */

    if (!int.TryParse(Request.QueryString["page"], out page))
    {
        page = 1;
    }

    /* This is your basic query to select the nodes you want */

    var nodes = Model.Content.Children.Where(x => x.DocumentTypeAlias == "NewsArticle").OrderBy(x=>x.CreateDate);

    int totalNodes = nodes.Count();
    int totalPages = (int)Math.Ceiling((double)totalNodes / (double)pageSize);

    /* Bounds checking */

    if (page > totalPages)
    {
        page = totalPages;
    }
    else if (page < 1)
    {
        page = 1;
    }

Hello Fuji,

I don't think I explained it on the best way to you. Please see screenshot bellow:

Can you help me update this code

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp "&#x00A0;"> ]>
<xsl:stylesheet 
  version="1.0" 
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
  xmlns:msxml="urn:schemas-microsoft-com:xslt" 
  xmlns:umbraco.library="urn:umbraco.library"
  exclude-result-prefixes="msxml umbraco.library">

<xsl:output method="xml" omit-xml-declaration="yes"/>

<xsl:param name="currentPage"/>

<xsl:template match="/">

  <xsl:variable name="items" select="$currentPage/ancestor-or-self::* [@isDoc and @level = 2]/* [@isDoc and string(umbracoNaviHide) != '1']"/>

<!-- The fun starts here -->

<xsl:if test="count($items) &gt; 0">
<ul>
<xsl:for-each select="$items">
  <li>
    <a href="{umbraco.library:NiceUrl(@id)}">
      <xsl:value-of select="@nodeName"/>
    </a>
  </li>
</xsl:for-each>
</ul>
    </xsl:if>

</xsl:template>

</xsl:stylesheet>

in order to have pagination , 10 articles per page?

Thanks, Adi

Hi Adi,

By Active you mean be clickable from the list if so update this part and it should get you working.

<ul>
  <xsl:for-eachselect="$about/*[@isDoc][not(umbracoNaviHide =1)]">
    <xsl:iftest="position() &lt; $jump and position() &gt;= ($jump - $itemsToDisplay)">
       <li><a href="{umbraco.library:NiceUrl(@id)}"><xsl:value-ofselect="@nodeName"/></a></li>  
     </xsl:if>   
  </xsl:for-each>
</ul>

However if you want an active class on the current paging try this

<xsl:templatename="for.loop">
                <xsl:paramname="i"/>
                <xsl:paramname="count"/>
                
                <xsl:iftest="$i &lt;=$count">
                        <xsl:iftest="$pageNumber!= $i">
                                <ahref="?page={$i}#about"><xsl:value-ofselect="$i"/></a>
                        </xsl:if>

                        <xsl:iftest="$pageNumber = $i">
                          <a  class="selected"><xsl:value-ofselect="$i"/></a>// Here is the active current Page 
                        </xsl:if>

                        <xsl:call-templatename="for.loop">
                                <xsl:with-paramname="i"select="$i + 1"/>
                                <xsl:with-paramname="count"select="$count">
                                </xsl:with-param>
                        </xsl:call-template>
                </xsl:if>
</xsl:template>

Hi Graeme,

thank you for posting very clean and useful Razlor example code but this time I decided to use XSLT.

All the best, Adi

Hello Fuji,

good news: code you suggestet is working successufully and now I have active links that are leading to articles.

However, I am still facing the issue I have described earlier which is giving me troubles. Please note that this is the current code (#code1):

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp "&#x00A0;"> ]>
<xsl:stylesheet 
  version="1.0" 
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
  xmlns:msxml="urn:schemas-microsoft-com:xslt"
  xmlns:umbraco.library="urn:umbraco.library" xmlns:Exslt.ExsltCommon="urn:Exslt.ExsltCommon" xmlns:Exslt.ExsltDatesAndTimes="urn:Exslt.ExsltDatesAndTimes" xmlns:Exslt.ExsltMath="urn:Exslt.ExsltMath" xmlns:Exslt.ExsltRegularExpressions="urn:Exslt.ExsltRegularExpressions" xmlns:Exslt.ExsltStrings="urn:Exslt.ExsltStrings" xmlns:Exslt.ExsltSets="urn:Exslt.ExsltSets" xmlns:umbraco.contour="urn:umbraco.contour" xmlns:PS.XSLTsearch="urn:PS.XSLTsearch" 
  exclude-result-prefixes="msxml umbraco.library Exslt.ExsltCommon Exslt.ExsltDatesAndTimes Exslt.ExsltMath Exslt.ExsltRegularExpressions Exslt.ExsltStrings Exslt.ExsltSets umbraco.contour PS.XSLTsearch ">


<xsl:output method="html" omit-xml-declaration="yes"/>

<xsl:param name="currentPage"/>
<xsl:variable name="about" select="umbraco.library:GetXmlNodeById('1303')"/><!-- Here is the NodeId from here you are pulling all the list of about -->


<xsl:variable name="itemsToDisplay" select="10"/> <!-- Number of items to display per page -->
<xsl:variable name="numberOfItems" select="count($about/*[@isDoc][not(umbracoNaviHide =1)])"/>
<xsl:variable name="jump" select="$itemsToDisplay * $pageNumber" />



<!-- Paging -->
<xsl:variable name="pageNumber">
  <xsl:choose>
    <xsl:when test="umbraco.library:RequestQueryString('page') = ''">
      <xsl:value-of select="1"/>
    </xsl:when>
    <xsl:otherwise>
      <xsl:value-of select="umbraco.library:RequestQueryString('page')"/>
    </xsl:otherwise>
  </xsl:choose>
</xsl:variable>        

<xsl:template match="/">
<!-- start writing XSLT -->
  <ul>
  <xsl:for-each select="$about/*[@isDoc][not(umbracoNaviHide =1)]">
    <xsl:if test="position() &lt; $jump and position() &gt;= ($jump - $itemsToDisplay)">
       <!--<li><xsl:value-of select="@nodeName"/></li>-->
        <li><a href="{umbraco.library:NiceUrl(@id)}"><xsl:value-of select="@nodeName"/></a></li>  
     </xsl:if>   
  </xsl:for-each>
</ul>


  <xsl:call-template name="for.loop">
  <xsl:with-param name="i">1</xsl:with-param>
  <xsl:with-param name="count" select="ceiling($numberOfItems div $itemsToDisplay)"></xsl:with-param>
</xsl:call-template>  


  </xsl:template>

    <xsl:template name="for.loop">
                <xsl:param name="i"/>
                <xsl:param name="count"/>

                <xsl:if test="$i &lt;=$count">
                        <xsl:if test="$pageNumber!= $i">
                                <a href="?page={$i}#about" ><xsl:value-of select="$i" /></a>
                        </xsl:if>

                        <xsl:if test="$pageNumber = $i">
                          <a  class="selected"><xsl:value-of select="$i"/></a>
                        </xsl:if>

                        <xsl:call-template name="for.loop">
                                <xsl:with-param name="i" select="$i + 1" />
                                <xsl:with-param name="count" select="$count">
                                </xsl:with-param>
                        </xsl:call-template>
                </xsl:if>
</xsl:template>

</xsl:stylesheet>

and this is the part of #code1 which is giving me troubles

umbraco.library:GetXmlNodeById('1303')

On my template, I have this default example code (#code2)

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp "&#x00A0;"> ]>
<xsl:stylesheet 
  version="1.0" 
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
  xmlns:msxml="urn:schemas-microsoft-com:xslt" 
  xmlns:umbraco.library="urn:umbraco.library"
  exclude-result-prefixes="msxml umbraco.library">

<xsl:output method="xml" omit-xml-declaration="yes"/>

<xsl:param name="currentPage"/>

<xsl:template match="/">

  <xsl:variable name="items" select="$currentPage/ancestor-or-self::* [@isDoc and @level = 2]/* [@isDoc and string(umbracoNaviHide) != '1']"/>

<!-- The fun starts here -->

<xsl:if test="count($items) &gt; 0">
<ul>
<xsl:for-each select="$items">
  <li>
    <a href="{umbraco.library:NiceUrl(@id)}">
      <xsl:value-of select="@nodeName"/>
    </a>
  </li>
</xsl:for-each>
</ul>
    </xsl:if>

</xsl:template>

</xsl:stylesheet>

which is showing list only if there is some content on current page. #code1 is showing only fixed value. Is it possible to update #code1 so it could show list only if there is some content on current page, same as it is defined on #code2?

Greetings, Adi

Hi Adi,

So you want to display only the nodes where there is Content in it right ?

You can modify the first code to this

<xsl:for-eachselect="$about/*[@isDoc][not(umbracoNaviHide =1)][bodyContent !='']">
    <xsl:iftest="position() &lt; $jump and position() &gt;= ($jump - $itemsToDisplay)">
       <!--<li><xsl:value-of select="@nodeName"/></li>-->
        <li><ahref="{umbraco.library:NiceUrl(@id)}"><xsl:value-ofselect="@nodeName"/></a></li>  
     </xsl:if>   
  </xsl:for-each>

Hi Fuji,

thank you very much for prompt reply.

I did as you suggested:

but result is this

so now I can't see any items on the list?

Greetings, Adi

Hi Adi,

Yes you wont see any items since this field is empty. In the example code i sent you before am using a bodyContent as umbraco field. 

Have you tried adding something to this field in the back end ?

Hello Fuji,

Ofcourse, I already have many articles which I have added long-time ago in back end. Your code is working great except that Pagination.xslt always pulls data only from one node '1303' and that is issue for me. Your code worked very good until I didn't modify this part

<xsl:for-eachselect="$about/*[@isDoc][not(umbracoNaviHide =1)][bodyContent !='']">
    <xsl:iftest="position() &lt; $jump and position() &gt;= ($jump - $itemsToDisplay)">
       <!--<li><xsl:value-of select="@nodeName"/></li>-->
        <li><ahref="{umbraco.library:NiceUrl(@id)}"><xsl:value-ofselect="@nodeName"/></a></li>  
     </xsl:if>   
  </xsl:for-each>

[#code2] works really good and it is showing list only if there is some data (it doesn't use fixed value '1303' as [#code1] which is good). That is biggest advantage of [#code2]

[#code1] on the other side is showing only values from node '1303' which is not good and it is always shown on every page that uses Template 'Textpage'. For example, [#code2] also shows on every article that uses Template 'Textpage' but if there is no data, it doesn't shows anything which is great. Your code [#code1] has great advantages: it splits 10 articles per page, adds numeration of pages, creates links but it is only missing one more advantage that [#code2] has, which I describe above.

I hope I exaplained it correctly, If I need to answer anything else please don't hasitate to tell me.

Thank you, Adi

Am getting a bite confused with [#code1][#code2]/!!!

Anyways looks like code1 is working as you expected so this is one thing. Now you want to do the same thing with code 2 right? If so then it will be something like

<xsl:variablename="items"select="$currentPage/ancestor-or-self::* [@isDoc and @level = 2]/* [@isDoc][not(umbracoNaviHide) != '1'][bodyContent !='']"/>

<!-- The fun starts here -->

<xsl:iftest="count($items) &gt; 0">
<ul>
<xsl:for-eachselect="$items">
  <li>
    <ahref="{umbraco.library:NiceUrl(@id)}">
      <xsl:value-ofselect="@nodeName"/>
    </a>
  </li>
</xsl:for-each>
</ul>
    </xsl:if>

Hello Fuji,

I have also becomed confused with codes at the end;) but I had no way to describe the issue, this way via forum. I have link of my website which I would like to send you so you could see it live and difference between [#code1] and [#code2] because I simply have no way to explain it via forum. Please send me your e-mail or perhaps if I could send you pm via twitter or something like that.

Thanks in advance.

All the best, Adi

Sure here is my twitter acc https://twitter.com/twit_fuji

Hi Fuji,

this is my twitter acc @mcmdesign_de Can you please follow me so I could send you direct message? I am following your acc already.

All the best, Adi

Thanks one more time Fuji!

All the best, Adi

Hi,

I am trying to mark this topic as solved and I don't know hot to do it;( Any suggestions?

Thank you, Adi

Hi Adi. There should be a green tick at the top of each comment. Click on the one that you think best answers your question.

Thank you;)

BR, Adi

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