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  • vijay 129 posts 152 karma points
    Dec 21, 2009 @ 14:34
    vijay
    0

    TinyMCE value how to save it?

    Hi all,

    I am able to get TinyMCE editor content but while saving it is giving following error.

    Server Error in '/' Application.

    A potentially dangerous Request.Form value was detected from the client (ctl00$ctl00$ContentPlaceHolderDefault$Farmscape-Admin-FAQ-DisplayQandA_1$content="<p>sample answer1.</...").

    Description: Request Validation has detected a potentially dangerous client input value, and processing of the request has been aborted. This value may indicate an attempt to compromise the security of your application, such as a cross-site scripting attack. You can disable request validation by setting validateRequest=false in the Page directive or in the configuration section. However, it is strongly recommended that your application explicitly check all inputs in this case.

    Exception Details: System.Web.HttpRequestValidationException: A potentially dangerous Request.Form value was detected from the client (ctl00$ctl00$ContentPlaceHolderDefault$Farmscape-Admin-FAQ-DisplayQandA_1$content="<p>sample answer1.</...").

    Source Error:

    The source code that generated this unhandled exception can only be shown when compiled in debug mode. To enable this, please follow one of the below steps, then request the URL:

    1. Add a "Debug=true" directive at the top of the file that generated the error. Example:

      <%@ Page Language="C#" Debug="true" %>

    or:

    2) Add the following section to the configuration file of your application:

    <configuration>
       <system.web>
           <compilation debug="true"/>
       </system.web>
    </configuration>

    Note that this second technique will cause all files within a given application to be compiled in debug mode. The first technique will cause only that particular file to be compiled in debug mode.

    Important: Running applications in debug mode does incur a memory/performance overhead. You should make sure that an application has debugging disabled before deploying into production scenario.


    Stack Trace:

    [HttpRequestValidationException (0x80004005): A potentially dangerous Request.Form value was detected from the client (ctl00$ctl00$ContentPlaceHolderDefault$Farmscape-Admin-FAQ-DisplayQandA_1$content="<p>sample answer1.</...").]
    System.Web.HttpRequest.ValidateString(String s, String valueName, String collectionName) +3213186
    System.Web.HttpRequest.ValidateNameValueCollection(NameValueCollection nvc, String collectionName) +108
    System.Web.HttpRequest.get_Form() +119
    System.Web.HttpRequest.get_Item(String key) +37
    umbraco.UmbracoDefault.Page_Load(Object sender, EventArgs e) +49
    System.Web.Util.CalliHelper.EventArgFunctionCaller(IntPtr fp, Object o, Object t, EventArgs e) +15
    System.Web.Util.CalliEventHandlerDelegateProxy.Callback(Object sender, EventArgs e) +34
    System.Web.UI.Control.OnLoad(EventArgs e) +99
    System.Web.UI.Control.LoadRecursive() +47
    System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) +6953
    System.Web.UI.Page.ProcessRequest(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) +154
    System.Web.UI.Page.ProcessRequest() +86
    System.Web.UI.Page.ProcessRequestWithNoAssert(HttpContext context) +18
    System.Web.UI.Page.ProcessRequest(HttpContext context) +49
    ASP.default_aspx.ProcessRequest(HttpContext context) +4
    System.Web.CallHandlerExecutionStep.System.Web.HttpApplication.IExecutionStep.Execute() +154
    System.Web.HttpApplication.ExecuteStep(IExecutionStep step, Boolean& completedSynchronously) +64

    Version Information: Microsoft .NET Framework Version:2.0.50727.42; ASP.NET Version:2.0.50727.42

     

  • Dirk De Grave 4541 posts 6021 karma points MVP 3x admin c-trib
    Dec 21, 2009 @ 14:42
    Dirk De Grave
    0

    Hi vijay,

    Please stop posting questions in multiple categories, it creates lots of 'noise', people most likely won't answer your question and it's hard to keep track of the answers people supply. I've removed your other post.

     

    Cheers,

    /Dirk

  • Ben Liyanage 11 posts 32 karma points
    May 28, 2010 @ 23:51
    Ben Liyanage
    0

    Ah, so where is the other post with the answer?  This is #1 in google with no answer...

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