random image from gallery

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Tony Kiernan 278 posts 341 karma points

Sep 30, 2011 @ 11:36
0

Random image from gallery
I am currently pulling the first image from a gallery folder using
```
Media gallery = new Media(media_id);
dynamic pic = gallery.Children.First();
```
How could I do something like this
```
dynamic pic = gallery.Children.Random();
```
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Kristoffer Eriksen 185 posts 465 karma points

Sep 30, 2011 @ 11:44

0

If you get the image gallery folder, you can get a random image with ImageGen.

http://our.umbraco.org/projects/website-utilities/imagegen

page 16 in the Documentation PDF.

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Tony Kiernan 278 posts 341 karma points

Oct 03, 2011 @ 12:14
0
Nice. Now, how do I get the folder? I'd assume something like
```
string str_folder = gallery.getProperty("Url").Value.ToString();
```
or
```
string str_folder = Model.NodeById(gallery_id).Url;
```
Neither of which is right
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Kristoffer Eriksen 185 posts 465 karma points

Oct 03, 2011 @ 12:24

0

Hey Tony

Well that depends on your solution, and how you created your gallery.

I just assumed, that since you wrote "from a gallery folder using" you already had the path for your gallery.

Are you using some sort of gallery package ?

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Tony Kiernan 278 posts 341 karma points

Oct 03, 2011 @ 22:21
0
Sorr, my bad. Read that as "from a media folder". The only package being used is
```
umbraco.cms.businesslogic.media
```
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Dan Diplo 1554 posts 6205 karma points MVP 6x c-trib

Oct 03, 2011 @ 22:32
1
In Umbraco 4.7.1 you can easily get a random image from a folder in the media library. Assuming you have the id of your folder:
```
dynamic folder = Library.MediaById(1054);
var randomImage = folder.Children.Where("nodeTypeAlias = \"Image\"").Random();
```
In my example 1054 is the id of the folder containing the images. The where part is only needed if your folder can potentially contain non-image files.
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