I don't know where you're getting your media identifier from, but you can do something like this:

var media = Model.MediaById(yourIdentifier);
<img src="@media.umbracoFile"/>

Hi Grant,

Thanks for quick reply.

Here is my whole old xslt  file :

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:Stylesheet [ <!ENTITY nbsp "&#x00A0;"> ]>
<xsl:stylesheet 
  version="1.0" 
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
  xmlns:msxml="urn:schemas-microsoft-com:xslt"
  xmlns:umbraco.library="urn:umbraco.library"
  exclude-result-prefixes="msxml umbraco.library">


<xsl:output method="xml" omit-xml-declaration="yes"/>

<xsl:param name="currentPage"/>

<xsl:template match="/">

<!-- start writing XSLT -->

<xsl:variable name="imgnr">
<xsl:choose>
  <xsl:when test="umbraco.library:GetItem('topbillede') &gt; 0" >
  <xsl:value-of select="umbraco.library:GetItem('topbillede')" />
  </xsl:when>
  <xsl:otherwise>
  <xsl:value-of select="1064" /> <!-- standardbillede -->
  </xsl:otherwise>
</xsl:choose>
</xsl:variable>

  <img alt="">
  <xsl:attribute name="src">

  <xsl:value-of select="umbraco.library:GetMedia($imgnr, 'false')/data[@alias= 'umbracoFile']"/>

  </xsl:attribute>

  </img>



</xsl:template>

</xsl:stylesheet> 

Please, have a look.
you can get better idea to solve my problem.

Thanks. 

You could do something like:

var mediaId = Model.topbillede != "0" ? Model.topbillede : "1064";

Assuming 'topbillede' is part of your Model (or, current document type) and is a string (you can easily adjust to handle integers instead). Otherwise, if it's on a parent or something you could try search recusively with 'Model._topbillede'. Then just as I showed above:

var media = Model.MediaById(mediaId);
<img src="@media.umbracoFile"/> 

Hi Tom,

thanks.
But, i get nothing , when i use as you told.

Thanks. 

Maybe something like

var media = Model.HasValue("topbillede") ? Library.MediaById(Model.Topbillede) : null;
if(media != null) {
  <img src="@media.Url"/>
} 

Hi All,

thanks a lot for your genuine help.

That works now.

Thanks. 

Hi all,

Last project was completed with success.

Now, working on another umbraco project.

but, getting some problem to get image file.

i used :

@{
  var media =Library.MediaById(Model.myMedia);
  <img src="@media.umbracoFile"/>}

Same as in precious one.

In previous project, i got the media url like : /media/12/something.jpg (that is working fine. http://studenterhusfonden.dk/)

now, in current project, i am getting the media url : ~/media/12/something.jpg. That is not displaying the image, if i remove "~" from this url working fine.

Thanks.
 

Are you still working in 4.7.1?

Hi,

No KD. :)

That was previous project about 2 months before.

Now i am working in 4.7.2.

Thaks.

Sorry for my late respose. I can't see that you are doing anything wrong.

In my latest project - witch is also 4.7.2 - I'm looping throug a media folder and view every image like this:

@foreach(var lightboxItem in mediaFolder.Children.Where("NodeTypeAlias == \"Image\"").Where("Visible").Skip(1))
{
 <a href="@lightboxItem.umbracoFile" rel="lightbox[@Model.UrlName]" title="@lightboxItem.umbracoFileAlt"></a>
}

And there are no problems. Sorry I could't help more.

Hi KD,

I will follow this syntax.

and np.

thanks for your help. :) 

Hi KD,

When i create scripting file with this above code.

It not saving the file. 

The Code :

@foreach(var lightboxItem in mediaFolder.Children.Where("NodeTypeAlias == \"Contact Persons\"").Where("Visible").Skip(1))
{
 <a href="@lightboxItem.umbracoFile" rel="lightbox[@Model.UrlName]" title="@lightboxItem.umbracoFileAlt"></a>
} 

The error  :

d:\Umbraco\ZDesign\macroScripts\634771649617052957_Testforimages.cshtml(2): error CS0103: The name 'mediaFolder' does not exist in the current context  

Thanks.

Arh yes... before the loop you must create a var called mediaFolder:

var mediaFolder = Library.MediaById(Model.whatEverYouHaveNamedTheParameter);

Thanks all. :)

It's working now.

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