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  • BarrySlisk 15 posts 35 karma points
    Aug 02, 2012 @ 10:22
    BarrySlisk
    0

    How to get properties of umbraco.NodeFactory.Node

    Yes, this should be simple...

    <p>type: @MyItem.GetType().ToString()</p>

    This returns umbraco.NodeFactory.Node

    I tried to get the name to see if I got the right node.

    @MyItem.GetProperty("Name").Value

    This fails when saving in Umbraco:

    'object' does not contain a definition for 'Name' and no extension method 'Name' accepting a first argument of type 'object' could be found (are you missing a using directive or an assembly reference?)

    @MyItem.GetProperty("Headline").Value this is the property I'm really interested in but this also fails. This is a TextString defined on the document type.

     

     

    Bonus question :)

    Can I convert umbraco.NodeFactory.Node to DynamicNode?

     

     

     

     

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  • BarrySlisk 15 posts 35 karma points
    Aug 02, 2012 @ 10:51
    BarrySlisk
    0

    I can get the name of the node like this of course (it was the node I expected so the other properties exist):

    @MyItem.Name

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  • BarrySlisk 15 posts 35 karma points
    Aug 02, 2012 @ 12:21
    BarrySlisk
    0

    Ok, I found out how to convert to dynamic. For other people in the future getting here, it's via the constructor of new DynamicNode().

    This means that I can get my properties by just dotting.

    Are there any advantages/disadvantages of non-dynamic nodes? Should I not just convert to dynamic always (for eaxample after .where clauses with lambda)?

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