I found the solution myself. I've given the solution here; it may help to someone.

dynamic CurrentNode = new DynamicNode().NodeById(CurrentNodeId);
var PreviousNodeId = CurrentNode.Previous().Id;
var NextNodeId = CurrentNode.Next().Id;

Hello,

Did you try something like this?

@Model.Content.Next()

Have a look at the Razor cheat sheets:

http://our.umbraco.org/projects/developer-tools/umbraco-v6-mvc-razor-cheatsheets

http://our.umbraco.org/projects/developer-tools/razor-dynamicnode-cheat-sheet

Jeroen

Hi,  

you can do something like this as well.

var next = new DynamicNode(m).GetFollowingSiblingNodes();
var previous = new DynamicNode(m).GetPrecedingSiblingNodes();

if(next.Any()) {
@next.Url }

if(previous.Any()) {
@previous.Url 
} 

How to get the previous & next node after sorting the list by date?

I also found this solution myself. It may help someone else.

            int NewNodeId = 0, i = 0;
            int[] NodeIdList = new int[mcList.Count];

            foreach (var mc in mcList.OrderByDescending(x => x.GetProperty("publishDate").Value))
            {
                NodeIdList[i] = mc.Id;
                i++;
            }
            i = 0;
            foreach (var mc in mcList.OrderByDescending(x => x.GetProperty("publishDate").Value))
            {
                if (mc.Id == NodeId)
                {
                    if (PrevOrNext == "Previous")
                    {
                        try { NewNodeId = NodeIdList[i - 1]; }
                        catch { NewNodeId = 0; }
                    }
                    else if (PrevOrNext == "Next")
                    {
                        try { NewNodeId = NodeIdList[i + 1]; }
                        catch { NewNodeId = 0; }
                    }
                }
                i++;
            }

Jebastin,

I had to do something similar although not with razor but similar principle. I had list of objects and for a given object in the list i need items next and previous to it. I found this on stackoverflow

        /// <summary>
    /// http://stackoverflow.com/questions/8759849/get-previous-and-next-item-in-a-ienumerable-using-linq
    /// </summary>
    /// <typeparam name="T"></typeparam>
    /// <param name="items"></param>
    /// <param name="matchFilling"></param>
    /// <returns></returns>
    public static IEnumerable<T> FindSandwichedItem<T>(this IEnumerable<T> items, Predicate<T> matchFilling)
    {
        if (items == null)
            throw new ArgumentNullException("items");
        if (matchFilling == null)
            throw new ArgumentNullException("matchFilling");

        return FindSandwichedItemImpl(items, matchFilling);
    }

    private static IEnumerable<T> FindSandwichedItemImpl<T>(IEnumerable<T> items, Predicate<T> matchFilling)
    {
        using (var iter = items.GetEnumerator())
        {
            T previous = default(T);
            while (iter.MoveNext())
            {
                if (matchFilling(iter.Current))
                {
                    yield return previous;
                    yield return iter.Current;
                    if (iter.MoveNext())
                        yield return iter.Current;
                    else
                        yield return default(T);
                    yield break;
                }
                previous = iter.Current;
            }
        }
        // If we get here nothing has been found so return three default values
        yield return default(T); // Previous
        yield return default(T); // Current
        yield return default(T); // Next
    }

        protected static List<Question> GetSandwichedQuestions(Question currentQuestion)
    {
        var allQuestions = TTContext.Current.CurrentSurvey.Questions;

        var sandwichedQuestions = allQuestions.FindSandwichedItem(q => q.QuestionId == currentQuestion.QuestionId).ToList();

        return sandwichedQuestions;
    }

This returns list of 3 questions the first one is previous midlde one is current and last one is next. You need to null test on prev and next just in case you are at end of begining of list

Regards

Ismail

Sorry for necroing this post, but any good solutions anno 2020? I can't seem to find the Next and Previous members...

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