attempting to get nice url from ultimate picker

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Jake 2 posts 32 karma points

Oct 04, 2013 @ 03:59

0

Attempting to get nice url from Ultimate Picker

I have been trying to get the nice url and node name from nodes selected in the Ultimate Picker property on a page and can't seem to get it right in Umbraco v6.1.5.

I am able to output the node ids as strings but not pass them into NiceUrl() to output. Here's what I have now to output the id strings:

@inherits Umbraco.Web.Mvc.UmbracoTemplatePage

<ul class="row">

@foreach(var link in CurrentPage.footerLinks.Split(',')) {

<li class="large-3 columns"><a href="#">@link.ToString()</a></li>

}

</ul>

This simply outputs a list of node ids of course. I have tried to use @Umbraco.NodeById(link.ToString()).NiceUrl() and variations of that to pass into the href but get compilation errors each time.

Thanks in advance guys.

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Jeavon Leopold 3074 posts 13631 karma points MVP 11x admin c-trib

Oct 04, 2013 @ 10:35

0

Hi Jake,

Essentially, I think you only need to use Umbraco.Content(link) but take a look at the Mvc dynamic example for ultimate picker here

You might also be interested in this package which takes away the need to split every time you need to output.

Jeavon

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Ali Sheikh Taheri 470 posts 1648 karma points c-trib

Oct 04, 2013 @ 10:36

Hi Jake,

just use @Umbraco.TypedContent(link).Url NiceUrl is obsolete.

so your code would be

@inherits Umbraco.Web.Mvc.UmbracoTemplatePage

<ul class="row">

          @foreach(var link in CurrentPage.footerLinks.Split(',')) 
          {
           var linkeNode = Umbraco.TypedContent(link.ToString());
          <li class="large-3 columns"><a href="@linkeNode.Url">@linkeNode.Name</a></li>

          }

</ul>

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Jake 2 posts 32 karma points

Oct 07, 2013 @ 20:16

0

Thanks guys, Ali's solution worked.

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Ali Sheikh Taheri 470 posts 1648 karma points c-trib

Oct 07, 2013 @ 20:17

0

Hi Jake,

Glad it worked, it would be great to mark it as solved so other people can easily find the answer.

Cheers

Ali

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