Hi Anders,

You can do it like this:

if (CurrentPage.HasValue("itemsPerSite")){ 
   @Umbraco.Field("itemsPerSite")
}

The HasValue check if the field has a value of the current page that you are viewing in the browser.

Hope this helps,

/Dennis

if(CurrentPage.HasProperty("itemsPerSite"))
    {        
    }

Thanks. for anwsers. Sorry forgot to say i am not able in usinge currentpage or model.

Is there another solution?

Hi Anders,

The @Umbraco.Field(string field) returns the value of that field from the Current Page. http://our.umbraco.org/documentation/Reference/Querying/UmbracoHelper/#Field%28stringfield%29 If you want to access a property on the parent or so, then you should have a look at the axis: http://our.umbraco.org/documentation/reference/templating/macros/razor/using-razor-axes

Or have a look on this cheat sheets, there a both dynamic razor and strongly typed razor, I know it says for V6, but you should be good with it in version 7 also. http://our.umbraco.org/projects/developer-tools/umbraco-v6-mvc-razor-cheatsheets

If you can tell more a about where the user should type in the value, of the field and your content structure, maybe we can help you closer to solve your issue.

Hope this helps,

/Dennis

Try this one, Remember to inherit the template from UmbracoTemplatePage

@inherits Umbraco.Web.Mvc.UmbracoTemplatePage

@{
    if (Model.Content.HasProperty("itemsPerSite"))
    {

    }

}

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