Hi Dan,

You could use .Descendants() the method returning either all pages (children, grandchildren and so on) below a given page in the content tree.

So something like this

node.Descendants()

You can see the different collections methods here https://our.umbraco.org/projects/developer-tools/umbraco-v6-mvc-razor-cheatsheets I know it says for Umbraco 6, but you can also use it for Umbraco 7. It´s just some pdf files with an overview of the different methods.

Hope this helps,

/Dennis

Thanks but it throws this error:

error CS1061: 'umbraco.NodeFactory.Node' does not contain a definition for 'Descendants' and no extension method 'Descendants' accepting a first argument of type 'umbraco.NodeFactory.Node' could be found (are you missing a using directive or an assembly reference?)

Hi Dan,

What if you do something like this:

var node = new DynamicNode(xxx);
var children = node.Descendants("yourDocTypeAlias");

I found it on stackoverflow here: http://stackoverflow.com/questions/20629673/where-on-specific-node-children-returns-does-not-contain-a-definition-for-where

Hope this helps,

/Dennis

Thanks but no joy I'm afraid. Maybe I should explain what I'm trying to achieve. I need to output JSON for all descendants of a node. I'm using this script which I'm trying to adapt as at hte moment it only returns child nodes

https://our.umbraco.org/projects/website-utilities/node-2-json

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