xslt passing nodes as a parameter to templates - XSLT

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Felix 46 posts 67 karma points

Jul 02, 2010 @ 06:44

XSLT - Passing nodes as a parameter to templates

im scratching my head here, hopefully someone can help me out.

Im trying to pass a set of nodes as a parameter to an xslt template. thats about it.

   <xsl:param name="currentPage"/>   

    <xsl:template match="/">
        <xsl:choose>
            <xsl:when test="$currentPage/@level=3">
                <xsl:call-template name="test">
                    <xsl:with-param name="nodes">
                        <xsl:value-of select="$currentPage/../node" />
                    </xsl:with-param>
                </xsl:call-template>
            </xsl:when>
            <xsl:otherwise>
                <xsl:call-template name="test">
                    <xsl:with-param name="nodes">
                        <xsl:value-of select="$currentPage/../../node" />
                    </xsl:with-param>
                </xsl:call-template>
            </xsl:otherwise>
        </xsl:choose>
    </xsl:template>

    <xsl:template name="test">
        <xsl:param name="nodes"></xsl:param>
        <xsl:value-of select="count($nodes)" />
    </xsl:template>

It errors on trying to print out the count of $nodes. Due to this i cant loop through it and do what i need to do. However just outputting $nodes within the test function does output values to the page. What am i doing wrong? :S

Thanks!

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Peter Duncanson 430 posts 1360 karma points c-trib

Jul 02, 2010 @ 11:55
1
You are using xsl:value-of which will just get the value of the node out as a string. Instead you just want to pass the node itself like so
```
<xsl:call-template name="test">
 <xsl:with-param name="nodes" select="$currentPage/../node" />
</xsl:call-template>
```
Its the difference between passing the value of a node or the node itself.

Hope that sorts it.
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Felix 46 posts 67 karma points

Jul 05, 2010 @ 03:17

0

thanks very much Peter!

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