Hi, I have a two level navigation menu generated with xslt. The thing is I want to output something different than the child nodes for a given doc type on the first level. The code I have is as follows

<ul class="sf-menu sf-navbar">
      <xsl:for-each select="$currentPage/ancestor-or-self::node [@level=$level]/node [string(data [@alias='umbracoNaviHide']) != '1']">
        <li>
          <a href="#">
            <xsl:value-of select="@nodeName"/>
          </a>
          <!-- Sub pages -->
          <xsl:if test="count(./node) &gt; 0">
            <ul>
              <xsl:choose>
                <xsl:when test="$currentPage/ancestor-or-self::node/@$nodeTypeAlias = 'Catalog'">
                  <li>Catalog!!</li>
                </xsl:when>
                <xsl:otherwise>
                  <xsl:for-each select="./node">
                    <li>
                      <xsl:if test="$currentPage/ancestor-or-self::node/@id = current()/@id">
                        <xsl:attribute name="class">current</xsl:attribute>
                      </xsl:if>
                      <a href="{umbraco.library:NiceUrl(@id)}">
                        <xsl:value-of select="@nodeName"/>
                      </a>
                      <a>
                        <xsl:value-of select="$currentPage/ancestor-or-self::node/@id"/>
                      </a>
                    </li>
                  </xsl:for-each>
                </xsl:otherwise>
              </xsl:choose>
            </ul>
          </xsl:if>
          <!-- End Sub pages -->
        </li>
      </xsl:for-each>
    </ul>

where I want to only output a li element when I find a Catalog doc type instead of its childs.