output an image inside xslfor each every iteration except the last one - XSLT

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North Krimsly 59 posts 80 karma points

Aug 02, 2010 @ 05:08

0

Output an image inside xsl:for-each, every iteration except the last one

Greetings all,

I'd like to output an image from my xslt script for every iteration of an xsl:for-each loop, except for the last iteration. Is there a way to "do something different" through some kind of an if-test, to see if we're in the last iteration of an xsl:for-each loop?

Here's the pseudo-code:

<xsl:for-each select="$currentPage/node [string(data [@alias='umbracoNaviHide']) != '1']">



</xsl:for-each>

Thanks in advance for your suggestions.

-NorthK

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Paul Blair 466 posts 731 karma points

Aug 02, 2010 @ 05:55
2
```
<xsl:if test="position() != last()">
...do stuff
</xsl:if>
```
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Chriztian Steinmeier 2800 posts 8791 karma points MVP 8x admin c-trib

Aug 02, 2010 @ 11:05
3
Hi North,

You can just exclude the last item from the processing by adding another predicate:
```
<xsl:for-each select="$currentPage/node[not(data[@alias = 'umbracoNaviHide'] = 1)][not(position() = last())]">
   
</xsl:for-each>
```
(Also, in XSLT it's more common to use not(something = value) instead of something != value)

/Chriztian
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North Krimsly 59 posts 80 karma points

Aug 03, 2010 @ 05:47

0

Guys,

Thanks a lot for taking the time to answer-- your suggestions worked perfectly!

-NorthK

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Output an image inside xsl:for-each, every iteration except the last one