I have some XSLT that succesfully gets all the child nodes for display as subnavigation.  I want that exact list of child nodes to display in the subnav of all child pages.  The first part of the code below works perfect, gives me the parent node on every page.

How do I get the second portion to work on child pages?  Is there a way to force it to travel up the tree and always start at the same node, no matter what page and how deep the XSLT is being displayed from?

<div class="block">
  <xsl:for-each select="$currentPage/ancestor-or-self::* [@template=1165 and string(umbracoNaviHide) != '1']">
    <h3>
      <a href="{umbraco.library:NiceUrl(@id)}">
        <xsl:value-of select="@nodeName"/>
      </a>
    </h3>
  </xsl:for-each>

  <ul class="products">
    <xsl:for-each select="$currentPage/* [@isDoc and string(umbracoNaviHide) != '1']">
      <xsl:variable name="subItems" select="umbraco.library:GetXmlNodeById(@id)/child::*  [@isDoc and string(umbracoNaviHide) != '1']"/>
      <li>
        <xsl:if test="count($subItems)">
          <xsl:attribute name="class">open</xsl:attribute>
        </xsl:if>
        <a href="{umbraco.library:NiceUrl(@id)}">
          <xsl:value-of select="@nodeName"/>
        </a>
        <xsl:if test="count($subItems)">
          <ul>
            <xsl:for-each select="$subItems">
              <li>
                <a href="{umbraco.library:NiceUrl(@id)}">
                  <xsl:value-of  select="@nodeName"/>
                </a>
              </li>
            </xsl:for-each>
          </ul>
        </xsl:if>
      </li>
    </xsl:for-each>
  </ul>

</div>