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  • Kasper Dyrvig 246 posts 379 karma points
    Aug 11, 2010 @ 16:00
    Kasper Dyrvig
    0

    Get specific number of random nodes from a variable parent

    I have searched a lot for a clear answer. But I think I have to ask: How do I view 8 random nodes from a variable parent?

    Thank you...

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  • Kasper Dyrvig 246 posts 379 karma points
    Aug 11, 2010 @ 16:14
    Kasper Dyrvig
    0

    Okay, now I got my XSLT to view the nodes. What I need now is so view only 8 of them and in random order.

    <xsl:for-each select="umbraco.library:GetXmlNodeById(@parentID)/*">
        <p>
          <a href="/skiferie?stay={@nodeName}"><xsl:value-of select="@nodeName" /></a></p>
    </xsl:for-each>

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  • Kasper Dyrvig 246 posts 379 karma points
    Aug 11, 2010 @ 16:33
    Kasper Dyrvig
    0

    This is getting wired...

    <xsl:for-each select="umbraco.library:GetXmlNodeById(@parentID)/*">
        <xsl:if test="position() &lt; 8">
          <p>
            <a href="/skiferie?stay={@nodeName}"><xsl:value-of select="stayName" /></a></p>
        </xsl:if>
      </xsl:for-each>

    That doesn't return enything... If I remove the if-test, I get all the content I need (and more).

    Any one who has an idea? 

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