Hi,

 I have a navigation menu for my website, which is generated by the pages/structure of the website.

I have this working however i have a yes/no property set in the document types to say if the page should be shown in the menu or not, however i cannot figure out how to do this. The alias for the property is called "showInNav".

Can anyone help me? I have no idea using XSLT. XSLT shown below....

Thanks.

<ul id="navmenu">

<xsl:for-each select ="$currentPage/ancestor-or-self::node[@level ='1']/descendant::node">

<xsl:if test="not (contains(current()/@nodeName,'News'))">

<xsl:if test="@level = 2">

<xsl:if test="count(child::node) > 0">

<li>

<xsl:if test ="$currentPage/parent::node/@id = current()/@id">

</xsl:if>

<a href="{umbraco.library:NiceUrl(current()/@id)}">

<xsl:value-of select="current()/@nodeName"/></a>

<ul>

<xsl:for-each select="current()/node">

<li>

<xsl:if test ="$currentPage/self::node/@id = current()/@id">

</xsl:if>

<a href="{umbraco.library:NiceUrl(current()/@id)}">

<xsl:value-of select="current()/@nodeName"/></a>

<ul>

<li><a href="#">test</a></li>

</ul>

</li>

</xsl:for-each>

</ul>

</li>

</xsl:if>

<xsl:if test="count(child::node) = 0">

<li>

<xsl:if test ="$currentPage/self::node/@id = current()/@id">

<xsl:attribute name="class" >selected</xsl:attribute>

</xsl:if>

<a href="{umbraco.library:NiceUrl(current()/@id)}">

<xsl:value-of select="current()/@nodeName"/></a>

</li>

</xsl:if>

</xsl:if>

</xsl:if>

</xsl:for-each>