Did you create this XSLT from the umbraco backend?

If not, go to the Developer-section and right-click on "XSLT" and choose "Create", you can select "Sitemap" and umbraco will generate a fully functional sitemap for your site (including the new XSLT-schema).

edit: Did you render the macro somewhere in your template?

Thanks for the reply Patrik.  I did render the macro in my template. I didn't look at the tool to generate the sitemap under developer section. Thanks for pointing that out.

I have worked out the following XSLT that works fine.

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp "&#x00A0;"> ]>
<xsl:stylesheet
  version="1.0"
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  xmlns:msxml="urn:schemas-microsoft-com:xslt"
  xmlns:umbraco.library="urn:umbraco.library"
  exclude-result-prefixes="msxml umbraco.library">

  <xsl:output method="html"/>

  <xsl:param name="currentPage"/>
  <xsl:variable name="maxLevelForSitemap" select="6"/>
  
  <xsl:template match="/">
        <div id="sitemap">
      <xsl:call-template name="drawNodes">
        <xsl:with-param name="parent" select="$currentPage/ancestor-or-self::* [@level = 1]"/>
      </xsl:call-template>
    </div>
  </xsl:template>

  <xsl:template name="drawNodes">
    <xsl:param name="parent"/>

    <ul>
      <xsl:for-each select="$parent/* [string(umbracoNaviHide) != '1' and @isDoc]">
        <li>
          <a href="{umbraco.library:NiceUrl(@id)}">
            <xsl:value-of select="@nodeName"/>
          </a>
          <xsl:call-template name="drawNodes">
            <xsl:with-param name="parent" select="."/>
          </xsl:call-template>
        </li>
      </xsl:for-each>
    </ul>
  </xsl:template>
</xsl:stylesheet>

Thanks again for the quick reply.

Thank you, thank you, thank you!  That worked a treat (the code from 611 didn't work).

Sai.

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