simple for each in xslt with new schema

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Fredrik Esseen 608 posts 904 karma points

Aug 30, 2010 @ 16:34

XSLT

Hi!

Im trying to build a simple newlist and created a document type "Newslist" with types "News" as child.

This is the xslt I use:

<div class="NewsListPane">
<xsl:for-each select="$currentPage/descendant::Newslist/node">
<xsl:sort select="@createDate" order="descending"/>
<xsl:if test="@nodeTypeAlias='News'" >
  <div class="NewsItem">
  <a href="{umbraco.library:NiceUrl(@id)}"><xsl:value-of select="@nodeName" /></a>
  </div>
</xsl:if>
</xsl:for-each>
</div>

This doesnt produce any news. What am I doing wrong?

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Jamie Howarth 306 posts 773 karma points c-trib

Aug 30, 2010 @ 17:23
0
Hey froad,

You're using /node which no longer exists in the Umbraco 4.5 XML schema.

You should be using:
```
<div class="NewsListPane">
<xsl:for-each select="$currentPage/*">
<xsl:sort select="@createDate" order="descending"/>
<xsl:if test="name()='News'" >
  <div class="NewsItem">
  <a href="{umbraco.library:NiceUrl(@id)}"><xsl:value-of select="@nodeName" /></a>
  </div>
</xsl:if>
</xsl:for-each>
</div>
```
Clarification: the * is a wildcard and your <xsl:if> block covers the rendering of your child News items.

HTH,

Benjamin
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Hendrik Jan 71 posts 137 karma points

Aug 30, 2010 @ 21:21
0
Its not really necessary but you should also use [@isDoc]

like:
$currentPage/descendant::Newslist/* [@isDoc]
but in your case you could even move to this:
$currentPage/descendant::Newslist/News
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