reading rss feed from picasaweb - XSLT

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maanehunden 61 posts 105 karma points

Sep 06, 2010 @ 18:43

reading rss feed from picasaweb.. ??

Hello fellow developers..

I am trying to grab an image gallery feed from picasaweb.. for my webpage,.. I've allready made a Wordpress fread reader http://laikaslair.dk/developer.aspx, but this picasa gallery feed is pulling my teath ,..

Her is a link to the feed,..
http://picasaweb.google.com/data/feed/base/user/101138924987420528379 ;

And her's how i've implemented my reader

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYpE xsl:stylesheet [ <!ENTITY nbsp "&#x00A0;"> ]>
<xsl:stylesheet 
    version="1.0" 
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
    xmlns:msxml="urn:schemas-microsoft-com:xslt"
    xmlns:umbraco.library="urn:umbraco.library" xmlns:Exslt.ExsltCommon="urn:Exslt.ExsltCommon" xmlns:Exslt.ExsltDatesAndTimes="urn:Exslt.ExsltDatesAndTimes" xmlns:Exslt.ExsltMath="urn:Exslt.ExsltMath" xmlns:Exslt.ExsltRegularExpressions="urn:Exslt.ExsltRegularExpressions" xmlns:Exslt.ExsltStrings="urn:Exslt.ExsltStrings" xmlns:Exslt.ExsltSets="urn:Exslt.ExsltSets" 
    exclude-result-prefixes="msxml umbraco.library Exslt.ExsltCommon Exslt.ExsltDatesAndTimes Exslt.ExsltMath Exslt.ExsltRegularExpressions Exslt.ExsltStrings Exslt.ExsltSets ">
 
 
<xsl:output method="xml" omit-xml-declaration="yes"/>
 
<xsl:param name="currentpage"/>
 
<xsl:template match="/">
 
  <!-- cache for  1.800 seconds(30min) -->
  <xsl:variable name="cacheRate" select="number(1800)"/>
 
  <xsl:variable name="picasaFeedUrl" >
    <!--find the main feed url-->http://picasaweb.google.com/data/feed/base/user/101138924987420528379
  </xsl:variable>
 
  <xsl:variable name="feedContentXML" select="umbraco.library:GetXmlDocumentByUrl($picasaFeedUrl, number($cacheRate))"/>
 
  <xsl:copy-of select="count($feedContentXML//entry)"/>
 
</xsl:template>
 
</xsl:stylesheet>

In my mind the "<xsl:copy-of select="count($feedContentXML//entry)"/>" code should render number 3 but the only thing i'm getting is 0.

and <xsl:copy-of select="$feedContentXML"/> renders the whole feed,.. ass it should

There's something i am missing.. )c:,

Suggestions plz..

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maanehunden 61 posts 105 karma points

Sep 06, 2010 @ 21:32

0

Ok.little bit progress here,.. i've noticed that the picase feed is not a RSS feed but an Atom feed,.. that could explain why i cant' parse it like I've done many times before.. .. Have anyone parsed this kind of format with XSLT,.. ?

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Hendrik Jan 71 posts 137 karma points

Sep 06, 2010 @ 22:20

0

Wel ofcourse you need to include the atom namespace etc..

This link might be usefull to you

http://snippets.dzone.com/posts/show/1162

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maanehunden 61 posts 105 karma points

Sep 06, 2010 @ 23:13

0

i did exactly that and added this to the top og my code

xmlns:atom="http://www.w3.org/2005/Atom/"
xmlns:media="http://search.yahoo.com/mrss/"

thanks

But the feed is till fighting back (c:

when i am probing for a special link item like this,..

<xsl:value-of select="./atom:link[@rel = 'alternate']"/>

i am getting Zilch but i can see there is at least three links in an entry
<xsl:value-of select="count(./atom:link)"/>

weired,..

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Hendrik Jan 71 posts 137 karma points

Sep 07, 2010 @ 06:28

0

if u want us to help you need to give some example code. Also the link to xml doesnt work.

But,i guess your code is something like this right?

<xsl:for-each select="./atom:link[@rel = 'alternate']">

<xsl:value-of select="."/>

</xsl:for-each>

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maanehunden 61 posts 105 karma points

Sep 07, 2010 @ 19:44
0
sorry i was a bit tired at that moment ..
```
  <xsl:for-each select="$feedContentXML//atom:entry">
    <xsl:copy-of select="count(./atom:link)"/>
    [<xsl:copy-of select="./atom:link[@rel = 'alternate']"/>]
    <xsl:copy-of select="count(./atom:link[@rel = 'alternate'])"/>
  </xsl:for-each>
```
where $feedContentXML holds the feed.. the wired thing is that <xsl:copy-of select="count(./atom:link)"/> gives number 3,
where as [<xsl:copy-of select="./atom:link[@rel = 'alternate']"/>] is somehow results in emty result(i've checked the feed there is an url in there).. and finally <xsl:copy-of select="count(./atom:link[@rel = 'alternate'])"/> gives a predictable 1..
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maanehunden 61 posts 105 karma points

Sep 07, 2010 @ 22:26
0
hi all,..
this seems to do the trick..
```
  <xsl:for-each select="$feedContentXML//atom:entry/atom:link[@rel = 'alternate']">
    <xsl:value-of select="@href"/>
  </xsl:for-each>
```
it returns all the expected Url's ..
thanx for all the help ,.. (c:

and happy coding..
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