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  • jonok 297 posts 658 karma points
    Sep 07, 2010 @ 11:47
    jonok
    0

    4.5 - Get position()=last() that is not empty

    I'm copying some of my old 4.0 xslt files into 4.5 and I have an xslt file that returns the last non-empty value. Basically it checks if the current page has an 'seoDescription' property value, and if not then returns the parent 'seoDescription' property value. But I can't work out how to get [position()=last()] to work in the 4.5 schema. Here is the code I'm trying to convert:

    <meta name='description'>
        <xsl:attribute name="content">
            <xsl:value-of select="$currentPage/ancestor-or-self::node [string(data[@alias='seoDescription'])!=''] [position()=last()] /data [@alias='seoDescription']" />
        </xsl:attribute>
    </meta>
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  • Chriztian Steinmeier 2800 posts 8790 karma points MVP 8x admin c-trib
    Sep 07, 2010 @ 11:57
    Chriztian Steinmeier
    0

    Hi jonok,

    Try something like this:

    <meta name='description'>
    <xsl:attribute name="content">
        <xsl:value-of select="$currentPage/ancestor-or-self::*[seoDescription[normalize-space()]][last()]/seoDescription" />
    </xsl:attribute>
</meta>

    /Chriztian

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  • jonok 297 posts 658 karma points
    Sep 07, 2010 @ 12:51
    jonok
    0

    Hi Chriztian, that doesn't quite seem to work - it's returning the parent property. For example when using the following page structure and when 'about us' is the current page...

    -Home
    --About us

    ...it is returning the 'home' seoDescription instead of the 'about us' seoDescription.

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  • Chriztian Steinmeier 2800 posts 8790 karma points MVP 8x admin c-trib
    Sep 07, 2010 @ 13:03
    Chriztian Steinmeier
    0

    Whoops! Pitfall... - replace the [last()] predicate with a [1] and it should take the right one. 

    /Chriztian

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  • jonok 297 posts 658 karma points
    Sep 07, 2010 @ 13:14
    jonok
    0

    Perfect - that did the trick. Thanks very much Chriztian.

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