What output do you get when you add these to your XSLT?

Search: <xsl:value-of select="$searchUrl"/> 
<br/>

Old: <xsl:value-of select="$oldCategory"/>
<br/>

New: <xsl:value-of select="$newCategory"/>

I get right values.

Old: categoryId=2560

New :categoryId=9999

And searchUrl, maybe you could post your whole XSLT here?

The replace function certainly does work, so something simple must be wrong.

Rich

Hi kukuwka,

I think the Replace function might not like the value of the $oldCategory and $newCategory variables - probably due to the whitespace/character-data.

Instead of using <xsl:value-of> inside the <xsl:variable> tags - try using the select?

<xsl:variable name="oldCategory" select="concat('categoryId=', $categoryId)" />
<xsl:variable name="newCategory" select="string('categoryId=9999')" />
<xsl:variable name="url" select="umbraco.library:Replace($searchUrl, $oldCategory, $newCategory)" />

Let us know if that works out.

Cheers, Lee.

This is my code:

<xsl:variable name="searchUrl" select="/macro/searchUrl"/>
<xsl:variable name="categoryId" select="umbraco.library:RequestQueryString('categoryId')"/>

<xsl:variable name="oldCategory">

    categoryId=<xsl:value-of select="$categoryId"/>

</xsl:variable>

<xsl:for-each select="$items">

      <xsl:variable name="newCategory">

               categoryId=<xsl:value-of select="@id"/>

      </xsl:variable>

      <xsl:variable name="url">
        
               < xsl:value-of select="umbraco.library:Replace($searchUrl, $oldCategory, $newCategory)"/>

       </xsl:variable>
     

     <a href="{$url}">
       
              <xsl:value-of select="$nodeName"/>

     </a>

</xsl:for-each>

Thanks,

kukuwka

Hi Lee,

Thank you very much.

It works.

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