picture with a link to another picture uploted in a same node

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Xanthos 2 posts 23 karma points

Oct 26, 2010 @ 23:43

0

Picture with a link to another picture uploted in a same node

well, I've made two upload controls, one for a thumbnail which is supposed to be shown as a part of a node and another one which should be opened directly in a browser to show image in full size when clicking on a thumbnail (in case someone is interested into saving picture and I don't like the idea to resize original size picture to fit into node).

I have no idea how to get the path to a uploaded photo, please help :(

                  <xsl:for-each select="$currentPage">
    <a href="location of a current()/photo">
   <xsl:choose>
  <xsl:when test="current()/photoThumbnail != ''">
  <img src="{current()/photoThumbnail}" alt="{@nodeName}"/>
  </xsl:when>
  <xsl:otherwise>
   </xsl:otherwise>
  </xsl:choose>
   </a>
        </xsl:for-each>

Thanks in advance.

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Lee Kelleher 4026 posts 15836 karma points MVP 13x admin c-trib

Oct 27, 2010 @ 10:47
0
Hi Xanthos,

First, just to confirm that you are using the Upload data-type, and not the media-picker data-type?

What is the property alias for the full-size photo?

Also, is your XSLT currently displaying the thumbnail images? As you shouldn't need to use a for-each to loop through the $currentPage, as there'd be only 1 iteration.

Try this instead:
```
<xsl:if test="$currentPage/photoThumbnail != ''">
    <a href="{$currentPage/photo}">
        <img src="{$currentPage/photoThumbnail}" alt="{$currentPage/@nodeName}"/>
    </a>
</xsl:if>
```
Cheers, Lee.
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Xanthos 2 posts 23 karma points

Oct 27, 2010 @ 11:25

1

Thank You, now it works as it was supposed so (thumbnail images were displayed before and I was using Upload data-type) :)

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