Are you using 4.5.x?  It looks like you are mixing the pre 4.5 and 4.5 schemas.

If using 4.5, try changing these lines:

<xsl:if test="($currentPage/@id=current()/@id and count(current()/node) > 0) or ($currentPage/@parentID = ./@id)">
     <ul>
         <xsl:for-each select="current()/node">

to:

<xsl:if test="($currentPage/@id=current()/@id and count(current()/* [@isDoc]) > 0) or ($currentPage/@parentID = ./@id)">
     <ul>
         <xsl:for-each select="current()/* [@isDoc]">

There might be other issues but that's the first thing I'd check :)

Thanks for the quick response....
First of all you are right about 4.5. I recently upgraded tot 4.5.

So i tried the following according your adjustments:

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [
    <!ENTITY nbsp "&#x00A0;">
]>
<xsl:stylesheet
  version="1.0"
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  xmlns:msxml="urn:schemas-microsoft-com:xslt"
  xmlns:umbraco.library="urn:umbraco.library"
  exclude-result-prefixes="msxml umbraco.library">

    <xsl:output method="xml" omit-xml-declaration="yes" />
    <xsl:param name="currentPage"/>
    <!-- Input the documenttype you want here -->
    <xsl:variable name="level" select="1"/>

    <xsl:template match="/">
    <!-- The fun starts here -->
    <xsl:for-each select="$currentPage/ancestor-or-self::* [@level = $level]/* [string(umbracoNaviHide) != '1' and @isDoc]">
      <xsl:choose>
        <xsl:when test="@nodeName= 'Nieuws'">
        </xsl:when>
        <xsl:otherwise>
          <li>
            <a href="{umbraco.library:NiceUrl(@id)}">
              <xsl:value-of select="@nodeName"/>
            </a>
            <xsl:if test="($currentPage/@id=current()/@id and count(current()/* [@isDoc]) > 0) or ($currentPage/@parentID = ./@id)">
            <ul>
                  <xsl:for-each select="current()/* [@isDoc]">
                  <li>
               <a href="{umbraco.library:NiceUrl(@id)}">
                  <xsl:value-of select="@nodeName"/></a>
                  </li>
                </xsl:for-each>
              </ul>
            </xsl:if>
          </li>
        </xsl:otherwise>
      </xsl:choose>
    </xsl:for-each>
  </xsl:template>
 </xsl:stylesheet>

Still not showing the submenu's.
A bit more info....
My template structure:

Master Page
         - Home Page
         - Text Page
                  - Sub Text Page

So all the Textpages form the 1e level of my menu. All the Text Page sub nodes (Sub Text Page) form the 2e level of my menu....al least that's what i want

Maarten

According to the code, the subpages will only show when you are on a main-level page that contains subpages, or when you are on one of the subpages.  Is that what you want?

Also was this working before you upgraded or is this something new you are adding?

Also the template structure doesn't really matter, it's more about the structure of your Content

Ok, first of all i haven't tested this of a prev. version of 4.5. This is accually the first time i'm working with sub level menu's
After republishing all pages it works..... but just as you say it should work.

The mainpage (home) only shows the 1e level menu items.  After clicking on one of the menu items only then the sub-menu items are loaded and the menu collapses. (you have to click twice...)

I'd like menu and sub-menus to be loaded at once on the home page...the sub-menus are hidden (css and script)

Acctually i only want to use the sub-menus as anchors for the current page.

So this looks something like this

Homepage
[menu]
  - products
  - links
  - contacts

Each page has several paragraphs (anchors)

  - products
      - product 1  (paragraph)
      - product 2  (paragraph)
      - etc.

By clicking on 'products' it should present the product page with product 1, 2 etc
So i dont know if making nodes of the sub menu items is the best way....

All open for suggestions.. 

Hi Tom,

Sorry for my late response....evering works fine now. Your directions were a great help.

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