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Hello probably really simple question, could someone tell me how to get the parent url of the current node in context using NiceUrl?
Hi Ian,
Just pass the parent's id into the function:
<xsl:value-of select="{umbraco.library:NiceUrl($currentPage/../@id)}" />
/Chriztian
Thanks
Hi, thought I'd mention that it can also be done directly on a template with:
<%= umbraco.library.NiceUrl(Node.GetCurrent().Parent.Id) %>
edit: oops just noticed this is in the XSLT forum - I can't delete this...
You can use:
<xsl:value-of select="{umbraco.library:NiceUrl($currentPage/@parentID)}" />
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getting parent url using niceUrl
Hello probably really simple question, could someone tell me how to get the parent url of the current node in context using NiceUrl?
Hi Ian,
Just pass the parent's id into the function:
/Chriztian
Thanks
Hi, thought I'd mention that it can also be done directly on a template with:
<%= umbraco.library.NiceUrl(Node.GetCurrent().Parent.Id) %>
edit: oops just noticed this is in the XSLT forum - I can't delete this...
You can use:
is working on a reply...