Hi all,

i am new to umbraco and xslt

i am trying to generate two level menu using xslt. for the first level menu i need to get the value of document property called MenuClassName. but it doesn't work, this is the code.

<xsl:param name="currentPage"/>

<!-- Input the documenttype you want here -->
<xsl:variable name="level" select="1"/>

<xsl:template match="/">

<!-- The fun starts here -->
<ul class="menu">
<xsl:for-each select="$currentPage/ancestor-or-self::node [@level=$level]/node [string(data [@alias='umbracoNaviHide']) != '1']">
 <li>
  <a href="{umbraco.library:NiceUrl(@id)}">
  <xsl:value-of select="@nodeName"/>
  <xsl:value-of select="current()[string(data [@alias='MenuClassItem'])]"/>
  </a>
  <ul class="acitem">
  <xsl:for-each select="current()/node [string(data [@alias='umbracoNaviHide']) != '1']">
    <li>
   <a href="{umbraco.library:NiceUrl(@id)}">
   <xsl:value-of select="@nodeName"/></a>
    </li>
  </xsl:for-each>
  </ul>
 </li>
</xsl:for-each>
</ul>

</xsl:template>