xpath macro parameter

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Simon Dingley 1474 posts 3431 karma points c-trib

Nov 20, 2010 @ 13:28
0

XPath Macro Parameter
Not sure if this is possible or not but I have a macro and for one of the parameters I would like to provide an XPath query that walks up the tree finding the closest node with a specific document property if the current node does not have one, and then pass that document property in as the parameter.

As an example:
```
<umbraco:macro runat="server" Alias="MyMacro" MyParam="string($currentPage/ancestor-or-self::* [@isDoc] /docProperty) != ''" /> 
```
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Richard Soeteman 4045 posts 12898 karma points MVP 2x

Nov 22, 2010 @ 10:40

0

Hi Simon,

You can use recursive Macro Properties for this. Normally you pass a parameter using [#documentProperty].This will only look in the current document. When you want to do a recursive lookup of the value, you can use [$documentProperty].

This WIKI explains the parameter syntax in detail.

Cheers,

Richard

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Simon Dingley 1474 posts 3431 karma points c-trib

Nov 22, 2010 @ 10:44

0

That's great Ricahrd thanks, it solved my problem. It is also worth mentioning that it was your "Meta tags, Umbraco:item control and runat="server" magic" blog post that led me to the solution.

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David Cardine 7 posts 27 karma points

Feb 17, 2011 @ 16:59

0

I'm looking at trying to do something similiar and I'm not having success.

i originally had my xpath query hardcoded in my xslt file and I'm extracting it in order to pass it through my macro. here's what i have.

<umbraco:Macro Alias="PostListMacro"  runat="server" sourcePath="[$currentPage/Posts/Year/Month/*]"></umbraco:Macro>

macro param: alias=sourcePath name=sourcePath type=text

<!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp " "> ]>
<xsl:stylesheet...>

<xsl:output method="xml" omit-xml-declaration="yes"/>
<xsl:template match="/">

<ul>
  <xsl:for-each select="/macro/sourcePath">
      more code
</xsl:for-each>
</ul>

</xsl:template>
</xsl:stylesheet>

did i set this up properly?

thanks for any help

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Simon Dingley 1474 posts 3431 karma points c-trib

Feb 17, 2011 @ 17:16
0
You don't need a parameter if you are going to use $currentPage because you can do that directly in your macro.

E.g.
```
<xsl:for-each select="$currentPage/Posts/Year/Month/*">
      more code
</xsl:for-each>
```
That said, if you are passing in a node as the source path you want the parameter type to perhaps be a content picker and then use:
```
<xsl:variable name="source" select="/macro/sourcePath" />
```
```
<xsl:for-each select="umbraco.library:GetXmlNodeById($source)">
      more code
</xsl:for-each>
```
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David Cardine 7 posts 27 karma points

Feb 18, 2011 @ 15:35

0

Thanks for the feedback. I ended up changing my plan like 100 times it felt like. new to xsl & umbraco and it's... fun in a crazy sort of way. I was able to get my page working with what you provided, but i ended up changing it b/c of needed to do something else.

thanks again!

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