Hello,

Using Umbraco 4.5.2 and having some difficulties writing a XSLT for my Sub Navigation. 

Here is my tree:

Now I am a little unclear on levels, but my understanding is:

Home - Level 1

News and Media - Level 2

Video - Level 3

Campbell River Video - Level 4

Now output is like this:

So far I am able to output the Level 2 Nav ($currentPage name and id)

But from there I am stumped. Here is my current XSLT:

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp "&#x00A0;"> ]>
<xsl:stylesheet 
  version="1.0" 
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
  xmlns:msxml="urn:schemas-microsoft-com:xslt" 
  xmlns:umbraco.library="urn:umbraco.library" xmlns:Exslt.ExsltCommon="urn:Exslt.ExsltCommon" xmlns:Exslt.ExsltDatesAndTimes="urn:Exslt.ExsltDatesAndTimes" xmlns:Exslt.ExsltMath="urn:Exslt.ExsltMath" xmlns:Exslt.ExsltRegularExpressions="urn:Exslt.ExsltRegularExpressions" xmlns:Exslt.ExsltStrings="urn:Exslt.ExsltStrings" xmlns:Exslt.ExsltSets="urn:Exslt.ExsltSets" xmlns:tagsLib="urn:tagsLib" xmlns:BlogLibrary="urn:BlogLibrary" 
  exclude-result-prefixes="msxml
 umbraco.library Exslt.ExsltCommon Exslt.ExsltDatesAndTimes 
Exslt.ExsltMath Exslt.ExsltRegularExpressions Exslt.ExsltStrings 
Exslt.ExsltSets tagsLib BlogLibrary ">


<xsl:output method="xml" omit-xml-declaration="yes" />

<xsl:param name="currentPage"/>

<xsl:template match="/">
  <!-- Sub Nav Heading -->
  <h1>
    <a href="{umbraco.library:NiceUrl($currentPage/@id)}"><xsl:value-of select="$currentPage/@nodeName"/></a>
  </h1>
  
<ul>
  <xsl:for-each select="$currentPage/ancestor-or-self::node [@level=2]/node [string(data [@alias='umbracoNaviHide']) != '1']">
    <xsl:if test="number($currentPage/@level)=3">
      <xsl:for-each select="$currentPage/child::node [@level=3]/node [string(data [@alias='umbracoNaviHide']) != '1']">
        <li>
          <a href="{umbraco.library:NiceURL($currentPage/@id)}"><xsl:value-of select="$currentPage/@nodeName"/></a>
        </li>
      </xsl:for-each>
    </xsl:if>
  </xsl:for-each>
</ul>

</xsl:template>

</xsl:stylesheet>

Any help or suggestions would be great! Still fairly new to XSLT.

Thanks,

Owen