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Hi there. I think I need some help with the new way of developing xslts.
I've got this sitemap in umbraco:
http://i55.tinypic.com/x0vjg9.jpg
But there's something wrong with my xslt, so it doesn't render the sitemap correctly.Kalender isn't a childnode to "Ren Artikel", but my xslt renders it that way.
Here's the code:
<nav> <h4> <xsl:value-of select="$startItem/menuTitle"/> </h4> <ul> <li> <xsl:choose> <xsl:when test="$currentPage/@id = $startItem/@id"> <xsl:attribute name="class">parent active current</xsl:attribute> </xsl:when> <xsl:otherwise> <xsl:attribute name="class">parent active</xsl:attribute> </xsl:otherwise> </xsl:choose> <a> <xsl:attribute name="href"> <xsl:value-of select="umbraco.library:NiceUrl($startItem/@id)"/> </xsl:attribute> <xsl:value-of select="$startItem/menuTitle"/> </a> <xsl:if test="count(child::*) > 0"> <ul> <xsl:for-each select="$startItem/*[@isDoc and name() !='IntranetFolder']"> <xsl:variable name="leftnav" select="current()/hideFromLeftMenu"/> <xsl:if test="($leftnav != '1' and name() !='IntranetFolder')"> <li> <xsl:choose> <xsl:when test="$currentPage/@id = current()/@id"> <xsl:attribute name="class">parent active current</xsl:attribute> </xsl:when> <xsl:otherwise> <xsl:choose> <xsl:when test="$currentPage/ancestor-or-self::*/@id = current()/@id"> <xsl:attribute name="class">parent active</xsl:attribute> </xsl:when> <xsl:otherwise> <xsl:attribute name="class">parent</xsl:attribute> </xsl:otherwise> </xsl:choose> </xsl:otherwise> </xsl:choose> <a> <xsl:attribute name="href"> <xsl:value-of select="umbraco.library:NiceUrl(current()/@id)"/> </xsl:attribute> <xsl:value-of select="current()/menuTitle"/> </a> <xsl:if test="count(child::*) > 0"> <ul> <xsl:for-each select="current()/*[@isDoc and name() !='IntranetFolder']"> <xsl:variable name="curleftnav" select="current()/hideFromLeftMenu"/> <xsl:if test="($curleftnav != '1' and name() !='IntranetFolder' )"> <li> <xsl:choose> <xsl:when test="$currentPage/ancestor-or-self::*/@id = current()/@id"> <xsl:attribute name="class">active current</xsl:attribute> </xsl:when> </xsl:choose> <a> <xsl:attribute name="href"> <xsl:value-of select="umbraco.library:NiceUrl(current()/@id)"/> </xsl:attribute> <xsl:value-of select="current()/menuTitle"/> </a> </li> </xsl:if> </xsl:for-each> </ul> </xsl:if> </li> </xsl:if> </xsl:for-each> </ul> </xsl:if> </li> </ul> </nav>
Any ideas why Kalender is rendered as a childnode to "Ren Artikel" even when it's not inside Umbraco?
http://i53.tinypic.com/xqhyip.jpg
This is how it's rendered in the html :(
Ok, so I fixed it my self.
it was a problem with my count. the menu wrote empty <ul> elements.
You might want to consider using (named) templates that recursively call themselves. DRY!
is working on a reply...
This forum is in read-only mode while we transition to the new forum.
You can continue this topic on the new forum by tapping the "Continue discussion" link below.
Continue discussion
problem with umbraco 4.5.x generating a submenu xslt
Hi there. I think I need some help with the new way of developing xslts.
I've got this sitemap in umbraco:
http://i55.tinypic.com/x0vjg9.jpg
But there's something wrong with my xslt, so it doesn't render the sitemap correctly.
Kalender isn't a childnode to "Ren Artikel", but my xslt renders it that way.
Here's the code:
<nav>
<h4>
<xsl:value-of select="$startItem/menuTitle"/>
</h4>
<ul>
<li>
<xsl:choose>
<xsl:when test="$currentPage/@id = $startItem/@id">
<xsl:attribute name="class">parent active current</xsl:attribute>
</xsl:when>
<xsl:otherwise>
<xsl:attribute name="class">parent active</xsl:attribute>
</xsl:otherwise>
</xsl:choose>
<a>
<xsl:attribute name="href">
<xsl:value-of select="umbraco.library:NiceUrl($startItem/@id)"/>
</xsl:attribute>
<xsl:value-of select="$startItem/menuTitle"/>
</a>
<xsl:if test="count(child::*) > 0">
<ul>
<xsl:for-each select="$startItem/*[@isDoc and name() !='IntranetFolder']">
<xsl:variable name="leftnav" select="current()/hideFromLeftMenu"/>
<xsl:if test="($leftnav != '1' and name() !='IntranetFolder')">
<li>
<xsl:choose>
<xsl:when test="$currentPage/@id = current()/@id">
<xsl:attribute name="class">parent active current</xsl:attribute>
</xsl:when>
<xsl:otherwise>
<xsl:choose>
<xsl:when test="$currentPage/ancestor-or-self::*/@id = current()/@id">
<xsl:attribute name="class">parent active</xsl:attribute>
</xsl:when>
<xsl:otherwise>
<xsl:attribute name="class">parent</xsl:attribute>
</xsl:otherwise>
</xsl:choose>
</xsl:otherwise>
</xsl:choose>
<a>
<xsl:attribute name="href">
<xsl:value-of select="umbraco.library:NiceUrl(current()/@id)"/>
</xsl:attribute>
<xsl:value-of select="current()/menuTitle"/>
</a>
<xsl:if test="count(child::*) > 0">
<ul>
<xsl:for-each select="current()/*[@isDoc and name() !='IntranetFolder']">
<xsl:variable name="curleftnav" select="current()/hideFromLeftMenu"/>
<xsl:if test="($curleftnav != '1' and name() !='IntranetFolder' )">
<li>
<xsl:choose>
<xsl:when test="$currentPage/ancestor-or-self::*/@id = current()/@id">
<xsl:attribute name="class">active current</xsl:attribute>
</xsl:when>
</xsl:choose>
<a>
<xsl:attribute name="href">
<xsl:value-of select="umbraco.library:NiceUrl(current()/@id)"/>
</xsl:attribute>
<xsl:value-of select="current()/menuTitle"/>
</a>
</li>
</xsl:if>
</xsl:for-each>
</ul>
</xsl:if>
</li>
</xsl:if>
</xsl:for-each>
</ul>
</xsl:if>
</li>
</ul>
</nav>
Any ideas why Kalender is rendered as a childnode to "Ren Artikel" even when it's not inside Umbraco?
http://i53.tinypic.com/xqhyip.jpg
This is how it's rendered in the html :(
Ok, so I fixed it my self.
it was a problem with my count. the menu wrote empty <ul> elements.
You might want to consider using (named) templates that recursively call themselves. DRY!
is working on a reply...
This forum is in read-only mode while we transition to the new forum.
You can continue this topic on the new forum by tapping the "Continue discussion" link below.