Okay, so after being a bit confused about how to get this going at first I've come up with a solution to a problem I've been having today.

I'm building a new site, its going to be on a flash front end, but part of the requirment is that the site must also be avalible in a html version. (for non flash clients, and also so the content can be easily sent out to people).

Due to the design, we can only display 6, of an infinite number of content items on a page.

So we need some kinda of paging system...

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This is my idea...

6 Items a page,

Page 1 = Items 1 -> 6
Page 2 = Items 7 -> 12
Page 3 = Items 13 -> 18
Page 4 = Items 19 -> 24

So what we need is two variables,

Starting Node (page number, minus 1, multiply that number by 6 and then add 1)
Finishing Node (page number multiplied by 6)

so I called these, $nodeStart and $nodeFinish

and we need a page number, so thats just a query string. nice and easy to do.

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This is all great, and nearly works, but I'm having trouble setting the nodeFinish. The probem is how do you filter the for-each, something like 'position=7'? I'm right in thinking this can't be done at the for-each level, as that wouldn't make sense. It needs to be done after as a filter right?

I'm sure its really simple to do... probally just 2 words, and a number!

I've posted the code below, so anyone can have a gander... I was quite suprised that I couldn't find any code to similar effect up on the forum. (I wrote a little bit of code to deal with what happens when there is no query string passed. Which would always be page 1.)

If your interested in seeing how this behaves follow these links;

http://dev.voodoodog.com/commercialsidents.aspx (no page ID)
http://dev.voodoodog.com/commercialsidents.aspx?Page=1 (start position working, but not finish)
http://dev.voodoodog.com/commercialsidents.aspx?Page=2 (start position working, but not finish)

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[code]

COUNT EQUALS

QS =

Node Start =

Node Finish =