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  • billiblu 37 posts 62 karma points
    Jan 13, 2011 @ 19:36
    billiblu
    0

    Generate list brothers pages

    XSLT

    I would like to create a list of all pages stored in the same node of current page.

    For example:

    - News List

            * News number 1

            * News number 2

            * News number 3

    When i see the page "News number 2" i want to create a list with "News number 1" and "News number 3".

    I am using 4.5.2 for .Net 3.5 version.

    With previous version I had no problem.

    Please help me.

    Thank you very much,

    Davide

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  • Kim Andersen 1447 posts 2196 karma points MVP
    Jan 13, 2011 @ 20:15
    Kim Andersen
    0

    Hi Davide.

    You should be able to accomplish this with the following piece of code:

    <xsl:for-each select="$currentPage/../*[@isDoc and @id!=$currentPage/@id]">
       <a href="{umbraco.library:NiceUrl(@id)}"><xsl:value-of select="@nodeName"/></a><br/>
    </xsl:for-each>

    /Kim A

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  • billiblu 37 posts 62 karma points
    Jan 13, 2011 @ 22:04
    billiblu
    0

    Hi Kim,

    thank you very much!

    I have not found an explanation in umbraco documentation.

    Can you tell me where I can read documentation about xslt on version 4.5?

    bye,

    Davide

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  • Tom Fulton 2030 posts 4998 karma points c-trib
    Jan 13, 2011 @ 22:07
    Tom Fulton
    0

    Hi Davide,

    Check out this wiki article that explains the differences between the 4.0 and 4.5 schemas.  Also includes a page with some examples.

    http://our.umbraco.org/wiki/reference/xslt/45-xml-schema

    -Tom

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  • billiblu 37 posts 62 karma points
    Jan 13, 2011 @ 23:00
    billiblu
    0

    Hi Tom,

    thank you for link!

    Davide

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