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billiblu 37 posts 62 karma points

Jan 13, 2011 @ 19:36

0

Generate list brothers pages

I would like to create a list of all pages stored in the same node of current page.

For example:

- News List

        * News number 1

        * News number 2

        * News number 3

When i see the page "News number 2" i want to create a list with "News number 1" and "News number 3".

I am using 4.5.2 for .Net 3.5 version.

With previous version I had no problem.

Please help me.

Thank you very much,

Davide

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Kim Andersen 1447 posts 2197 karma points MVP

Jan 13, 2011 @ 20:15

Hi Davide.

You should be able to accomplish this with the following piece of code:

<xsl:for-each select="$currentPage/../*[@isDoc and @id!=$currentPage/@id]">
   <a href="{umbraco.library:NiceUrl(@id)}"><xsl:value-of select="@nodeName"/></a><br/>
</xsl:for-each>

/Kim A

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billiblu 37 posts 62 karma points

Jan 13, 2011 @ 22:04

0

Hi Kim,

thank you very much!

I have not found an explanation in umbraco documentation.

Can you tell me where I can read documentation about xslt on version 4.5?

bye,

Davide

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Tom Fulton 2030 posts 4998 karma points c-trib

Jan 13, 2011 @ 22:07

0

Hi Davide,

Check out this wiki article that explains the differences between the 4.0 and 4.5 schemas. Also includes a page with some examples.

http://our.umbraco.org/wiki/reference/xslt/45-xml-schema

-Tom

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billiblu 37 posts 62 karma points

Jan 13, 2011 @ 23:00

0

Hi Tom,

thank you for link!

Davide

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Generate list brothers pages