for each select by path - XSLT

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Nico 16 posts 37 karma points

Feb 05, 2011 @ 03:06

0

for-each select by path

XSLT

Hi all,

   I've done many search (manybe wrong) and I think I come to topics responding for previous version of Umbraco so, I'm a little confused...

I have a Content structure as

   Default
      Projects
      Contacts
      etc...

   I need to do a simple for-each select using a known path of a node in xslt. I've tried somethings like

<xsl:for-each select="//Default/Projects">
   or
<xsl:for-each select="$currentPage/ancestor-or-self::root/* [@nodeName = 'Projets']/nodes">

   but with no results.

   Anybody have a hint ?

   Thanks in advance.
   NF

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Daniel Bardi 927 posts 2562 karma points

Feb 05, 2011 @ 10:24

0

Try this:

<xsl:for-each select="$currentPage/* [name() = 'Projects']">

But if you know the path and it's only one node just do this:

<xsl:variable name="projectsNode" select="$currentPage/* [name() = 'Projects' and position() = 1]"/>

looks like it should work.

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Nico 16 posts 37 karma points

Feb 05, 2011 @ 17:49
0
Hi,

thanks for your answer but, it seems not to work... my Projects node is in the root node, not necessarly in the $currentPage.

A simple test like this :
```
            <xsl:for-each select="$currentPage/* [name() = 'Projects']">
              bla 
            </xsl:for-each>
```
is not working.

NF
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Kim Andersen 1447 posts 2196 karma points MVP

Feb 05, 2011 @ 21:08
1
Hi Nico

If you want to iterate through the childnodes of the "Projects"-node you should be able to use this piece og code:
```
<xsl:for-each select="$currentPage/ancestor-or-self::*[@isDoc and @level='1']/*[@nodeName = 'Projects' and @isDoc]/*[@isDoc]">
```
/Kim A
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Kim Andersen 1447 posts 2196 karma points MVP

Feb 09, 2011 @ 18:22

0

Hi Nico

Did you ever find a solution to this problem?

/Kim A

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for-each select by path