So i'm using one of the navigation templates for the New XSLT Schema, the code is as follows:

 <ul>
       <li>
         <xsl:if test="$currentPage/@id = $currentPage/ancestor-or-self::* [@level=$level]/@id">
             <xsl:attribute name="class">home active</xsl:attribute>
         </xsl:if>
         <a href="/">Home</a>
       </li>
      <xsl:for-each select="$currentPage/ancestor-or-self::* [@level=$level]/* [@isDoc and string(umbracoNaviHide) != '1']">
  <li>
     <xsl:if test="@id = $currentPage/@id">
        <xsl:attribute name="class">active</xsl:attribute>
      </xsl:if>
    <a class="navigation" href="{umbraco.library:NiceUrl(@id)}">
      <span><xsl:value-of select="@nodeName"/></span>
    </a>
  </li>
  
  
</xsl:for-each>
</ul>

What I'm trying to achieve, is that if one of the nav items is of a certain document type "ExternalLink" instead of linking the a href to the {umbraco.library:NiceUrl...} I'd like it to pull the link from a field i've added to the document type called "externalLinkAddress"

I believe i could so something like "data [@alias = 'externalLinkAddress']" for the link, i'm just not sure how to apply the "when" statement"

<xsl:choose>
 <xsl:when test="$ExternalLink">
  
<li>
     <xsl:if test="@id = $currentPage/@id">
        <xsl:attribute name="class">active</xsl:attribute>
      </xsl:if>
    <a class="navigation" href="{umbraco.library:NiceUrl(@id)}">
      <span><xsl:value-of select="@nodeName"/></span>
    </a>
  </li> </xsl:when>
 <xsl:otherwise>
  
<li>
     <xsl:if test="@id = $currentPage/@id">
        <xsl:attribute name="class">active</xsl:attribute>
      </xsl:if>
    <a class="navigation" href="data [@alias = 'externalLinkAddress']">
      <span><xsl:value-of select="@nodeName"/></span>
    </a>
  </li> </xsl:otherwise>
</xsl:choose>

Any help would be appreciated!

Thank you,

Amir