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  • Claus Nedergaard 62 posts 104 karma points
    Feb 15, 2011 @ 14:50
    Claus Nedergaard
    0

    Show news on fontpage

    Hi all! Iv'e been struggling with upgrading my newslist  to the new schema.

    The xslt saves fine but genereats no output at all. Only the <ul> tag gets generated in the browser.

    I have my newspage (total overview) on level 1 with the news items below that.

    The page with the newslist is also on level 1.

            
    <xsl:variable name="SortOrder" select="$currentPage/ancestor-or-self::* [@isDoc and @level = 1]//* [@isDoc and @nodeTypeAlias = 'ndmNyhederAktivitetsListe']/sortOrder" /> 
    <xsl:variable name="SortBy" select="$currentPage/ancestor-or-self::* [@isDoc][@level=1]//* [@isDoc and @nodeTypeAlias = 'ndmNyhederAktivitetsListe']/sortBy" />
    <xsl:variable name="NumberofItemsToDisplay" select="$currentPage/antalNyhederForsiden" />
    <xsl:template match="/">
    <xsl:variable name="DataType">  
        <xsl:choose> 
            <xsl:when test="$SortBy='sortOrder'"> 
                <xsl:value-of select="'number'" /> 
            </xsl:when> 
            <xsl:otherwise> 
                <xsl:value-of select="'text'" /> 
            </xsl:otherwise> 
        </xsl:choose> 
    </xsl:variable>
           

    <ul id="NewsList">
    <xsl:for-each select="$currentPage/ancestor-or-self::* [@isDoc and @level = 1]//* [@isDoc and @nodeTypeAlias = 'ndmNyhederAktivitetsListe'] [string(umbracoNaviHide) != '1']">
    <xsl:sort select="@*[name() = $SortBy]" order="{$SortOrder}" data-type="{$DataType}"/>
     <xsl:if test="position()&lt;= $NumberofItemsToDisplay">  
      <xsl:variable name="Class">  
       <xsl:choose> 
        <xsl:when test="@nodeTypeAlias='ndmAktivitet'"> 
         <xsl:value-of select="'ndmAktivitet'" /> 
        </xsl:when> 
        <xsl:otherwise> 
         <xsl:value-of select="'ndmNyhed'" /> 
        </xsl:otherwise> 
       </xsl:choose> 
      </xsl:variable>
      <li class="{$Class}">
       <a title="{@nodeName}" href="{umbraco.library:NiceUrl(@id)}">
        <strong><xsl:value-of select="@nodeName"/></strong><br/>
        <xsl:if test="./@updateDate !=''">    
         <em><xsl:value-of select="umbraco.library:FormatDateTime(./@updateDate, 'd. MMMM yyyy, ')"/></em>
        </xsl:if> <xsl:value-of select="@writerName"/>
       </a>
      </li>
     </xsl:if>
    </xsl:for-each>
    </ul>
    </xsl:template>
    </xsl:stylesheet>

    Please advice.

    Thanks in advance.

  • Jan Skovgaard 11280 posts 23678 karma points MVP 11x admin c-trib
    Feb 15, 2011 @ 15:27
    Jan Skovgaard
    0

    Hi Claus

    I think it's the @nodeTypeAlias that is bugging you here. Since the elements are named after the nodeTypeAlias it's not an attribute in the XML anymore.

    So therefore I think you should try and change your expression from

             <xsl:variable name="SortOrder" select="$currentPage/ancestor-or-self::* [@isDoc and @level = 1]//* [@isDoc and @nodeTypeAlias = 'ndmNyhederAktivitetsListe']/sortOrder" /> 

    to

             <xsl:variable name="SortOrder" select="$currentPage/ancestor-or-self::* [@isDoc and @level = 1]//* [@isDoc and ndmNyhederAktivitetsListe]/sortOrder" />

    Try it out and see if it's working for you. And do remember to change it everywhere you make use of the @nodeTypeAlias attribute.

    /Jan

  • kows 81 posts 151 karma points c-trib
    Feb 15, 2011 @ 15:30
    kows
    0

    if above doesn't work maybe (also think its @nodeTypeAlias) :

    name() = 'ndmNyhederAktivitetsListe'

  • Claus Nedergaard 62 posts 104 karma points
    Feb 15, 2011 @ 16:52
    Claus Nedergaard
    0

    Thanks guys...you are lifesavers :-)

    Turned out you were both spot on. the nodeTypeAlias was the culprit.

    Tried Jans proposal first and the xslt file saved ok - but still no output. But using kows expression was the one that worked for me.

    Thanks! 

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