Hi Bart

try changing the value-of to this

<xsl:value-of select="current()/root/node/@nodeName" /> or <xsl:value-of select="current()/node/@nodeName" /> perhaps.

Does this help?

/Jan

Hi Jan,

I get an output wehn i use:

 <xsl:for-each select="tags:getEverythingWithTags('test')">
       <xsl:value-of select="current()/root/node/@nodeName" />
 </xsl:for-each>

but only the first node of  the 2 nodes is shown.

<root>
<node id="1076" parentID="1057" level="2" writerID="0" sortOrder="7" createDate="2011-01-04T22:18:20" nodeName="Ap" path="-1,1057,1076" />
<node id="1077" parentID="1057" level="2" writerID="0" sortOrder="0" createDate="2011-01-04T22:18:40" nodeName="Mt" path="-1,1057,1077" />
</root>

Hi Bart

But in the XML output you posted in the first post you also only got 2 <node> elements returned, right?

Are there more than 2 posts tagged with "test"?...

/Jan

Hi Jan,

Just checked the output of <xsl:copy-of select="tags:getEverythingWithTags('test')"/> with the xslt viewer and discoverd
that the node isn't closed correctly

Bart 

So there should actually be 3 nodes?

Have you tried to go to the "Content" node and right click it choosing "Republish entire site"? (this updates the XML cache)

Just to make sure that the XML is properly structured. You could also check to see if there is XML in the umbraco.config that is not wellformed.

/Jan

Hi Bart (& Jan)

The XSLT Visualizer munges the output - you have to wrap a textarea around stuff you copy-of, in order to see the correct output.

It seems you're just getting the tagged nodes wrapped in a root element, which means that you should modify your for-each to something like this:

<xsl:for-each select="tags:getEverythingWithTags('test')/root/node">
    <xsl:value-of select="@nodeName"/>
</xsl:for-each>

/Chriztian

Hi Chriztian,

That work fine.

Thnx a lot

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