Anyone? :)

Hi Bo,

you could try following.

Here what i am doing is that first i take all nodes of hotel type and then select one random node id of hotel amongst them and then i loop through all the nodes and select the one which is marked for random.

Let me know if this helps.

Regards,

Jigar ([email protected])

 <xsl:variable name="HotelRoot" select="umbraco.library:GetXmlAll()//node[@nodeTypeAlias ='Hotel'] />

        <xsl:variable name="HotelNodeSet" select="$HotelRoot" />

        <xsl:variable name="numNodes" select="count($HotelNodeSet)" />
        <xsl:variable name="RandomID" select="floor(Exslt.ExsltMath:random() * $numNodes) + 1"/>
        <xsl:for-each select="$HotelNodeSet[position() = $RandomID]">

            <div class="header-arrow-home">
                <a href="{umbraco.library:NiceUrl(@id)}">FEATURED Hotel</a>
            </div>
            <div id="future-content">
                <h3>
                    <xsl:value-of select="data [@alias = 'Hotel_Name']"/>

                </h3>
                <p class="larg14">
                    <xsl:value-of select="substring(umbraco.library:StripHtml(data [@alias = 'Hotel_Short_Details']),1,400)" />....
                </p>

                <a href="{umbraco.library:NiceUrl(@id)}" class="more-button">&nbsp;</a>
            </div>

Hi Jigar,

Sorry for the *very* delayed response - I honestly forgot about this post.#embarassed

While it certainly lists a random node, I would like it to list at least 5 random nodes :-/ simply can't figure it out...

Got it solved with some help from javascript ;-)

This did the trick:

  <xsl:variable name="allSpots" select="umbraco.library:GetXmlAll()//PartnerSpot" />
  <xsl:variable name="spotNodeSet" select="$allSpots" />

  <xsl:for-each select="$spotNodeSet">
    <xsl:sort select="rdm:Random(4)" order="descending" />
     <xsl:if test="position() &lt;= 4">
      <p><xsl:value-of select="current()/@nodeName" /></p>
    </xsl:if>
  </xsl:for-each> 

Got it solved with some help from javascript ;-)

This did the trick:

  <xsl:variable name="allSpots" select="umbraco.library:GetXmlAll()//PartnerSpot" />
  <xsl:variable name="spotNodeSet" select="$allSpots" />

  <xsl:for-each select="$spotNodeSet">
    <xsl:sort select="rdm:Random(4)" order="descending" />
     <xsl:if test="position() &lt;= 4">
      <p><xsl:value-of select="current()/@nodeName" /></p>
    </xsl:if>
  </xsl:for-each> 

Hi Simon,

Thanks for your solution! I've actually tried that C# GetRandom method before and it works just aswell as my javascript hack ;-)  Thanks for your help and time! Greatly appreciated.

For the benefit of others can you show the full solution including the Random() method?

Oh, sorry - didn't see I missed out the js method. Here's the full XSLT file:

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp "&#x00A0;"> ]>
<xsl:stylesheet 
  version="1.0" 
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
  xmlns:msxml="urn:schemas-microsoft-com:xslt"
  xmlns:rdm="http://www.umbraco.org/"
  xmlns:umbraco.library="urn:umbraco.library" xmlns:Exslt.ExsltCommon="urn:Exslt.ExsltCommon" xmlns:Exslt.ExsltDatesAndTimes="urn:Exslt.ExsltDatesAndTimes" xmlns:Exslt.ExsltMath="urn:Exslt.ExsltMath" xmlns:Exslt.ExsltRegularExpressions="urn:Exslt.ExsltRegularExpressions" xmlns:Exslt.ExsltStrings="urn:Exslt.ExsltStrings" xmlns:Exslt.ExsltSets="urn:Exslt.ExsltSets" xmlns:PS.XSLTsearch="urn:PS.XSLTsearch" 
  exclude-result-prefixes="rdm
 msxml umbraco.library Exslt.ExsltCommon Exslt.ExsltDatesAndTimes 
Exslt.ExsltMath Exslt.ExsltRegularExpressions Exslt.ExsltStrings 
Exslt.ExsltSets PS.XSLTsearch">


<xsl:output method="xml" omit-xml-declaration="yes"/>

<xsl:param name="currentPage"/>
<msxml:script language="JavaScript" implements-prefix="rdm">
    function Random(r) { return Math.ceil(Math.random()*r); }
</msxml:script>
<xsl:template match="/">

<!-- start writing XSLT -->   
  <xsl:variable name="allSpots" select="umbraco.library:GetXmlAll()//PartnerSpot" />
  <xsl:variable name="spotNodeSet" select="$allSpots" />

  <xsl:for-each select="$spotNodeSet">
    <xsl:sort select="rdm:Random(4)" order="descending" />
     <xsl:if test="position() &lt;= 4">
      <p><xsl:value-of select="current()/@nodeName" /></p>
    </xsl:if>
  </xsl:for-each>  
</xsl:template>

</xsl:stylesheet>

Thanks again :-)

But Do goes that function if browser block javascript?

The script is processed before the results are sent to the browser so the answer is yes as far as I am aware.

Hi Bo Mortensen.. Thanks for the code sample..

It looks like the cleanest code to generate random numbers in XSLT.. also just got to know from your code we can use Javascript functions like that in XSLT :)

is working on a reply...