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Daniel Horn 319 posts 344 karma points

Mar 13, 2011 @ 13:52

I have this structure:

- News

-- 2011

--- news 1

--- news 2

-- 2010

--- news 4

--- news 5

-- 2009

On my frontpage I show both news from 2011 and 2010 - so how do i point them into the different pages (2011 and 2010).

So when you click on news 1 you go to the 2011 page and when you click on news 4 you go to the 2010 page?

It's my url3 i need to change to point to the parent of those news items.

Here's what i'm trying:

        <dl class="morenews">
           <dt><xsl:value-of select="$currentPage/ancestor-or-self::*[@isDoc]/flereNyhederOverskrift" /></dt>
          
            <xsl:for-each select="$currentPage/descendant-or-self::Nyhed [@isDoc]">
              <xsl:sort select="nyhedsdato" order="descending"/>
              <xsl:if test="position() &gt;3 and position() &lt;=6">
                <xsl:variable name="url3" select="$currentPage/parent::*[@isDoc]/nyhed"/>
                <xsl:variable name="url2" select="parent::node" />  
                
              <dd><a href="{$url3}#{@urlName}">
               <xsl:value-of select="titelLinie1"/></a></dd>
                  </xsl:if></xsl:for-each>
          
                   <dd class="allnews"><a>
                <xsl:if test="$url1 != ''">  
                <xsl:attribute name="href"><xsl:value-of select="umbraco.library:NiceUrl($url1)"/></xsl:attribute>
                </xsl:if><xsl:value-of select="$currentPage/ancestor-or-self::*[@isDoc]/lsFlereNyhederLinkTekst" /></a></dd>
               
                </dl>
      </div>

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Kim Andersen 1447 posts 2196 karma points MVP

Mar 13, 2011 @ 14:13
1
Hi Daniel

If you want the $url3 to contain a link to the parent node try this:
```
<xsl:variable name="url3" select="umbraco.library:NiceUrl($currentPage/../@id)"/>
```
/Kim A
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Jan Skovgaard 11280 posts 23678 karma points MVP 11x admin c-trib

Mar 13, 2011 @ 14:58

0

Hi Daniel

Perhpas you could also make sure that the link is always pointing to the second or third id in the @path attribute? (Or whatever place the id has in the path attribute).

This attributes contains a comma seperated list of nodeid's that makes up the path to the current node.

So by splitting the content of this attribute using umbraco.library:Split() you can always go to the correct id by writing something like...

<xsl:variable name="parent" select="umbraco.library:Split(@path,',')/values/value[2]" />

I hope this makes sense.

/Jan

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Chriztian Steinmeier 2800 posts 8790 karma points MVP 8x admin c-trib

Mar 13, 2011 @ 22:59
2
Hi Daniel,

To get the url3 variable to point to the parent of the page you're currently at in the loop,

you should use current() instead of $currentPage - but in this case you can just ditch the

"$currentPage/" part. I *think* what you're aiming at is really something like Kim's suggestion,

but not using $currentPage - so effectively:
```
<xsl:variable name="url3" select="umbraco.library:NiceUrl(../@id)" />
```
@Jan: Don't mess with the @path attribute - it's usually much better to use the ancestor-or-self:: axis to access those nodes.

/Chriztian
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Jan Skovgaard 11280 posts 23678 karma points MVP 11x admin c-trib

Mar 14, 2011 @ 07:25

0

Hi Chriztian

Yes of course - just meant as an alternative solution :-)

/Jan

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Kim Andersen 1447 posts 2196 karma points MVP

Mar 14, 2011 @ 09:14

0

Holy smokes! How did I not notice that we where inside a loop :P

Yeah, of course you shouldn't use $currentPage then, but do like Chriztian says.

/Kim A

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Daniel Horn 319 posts 344 karma points

Mar 14, 2011 @ 16:15

0

Thanks guys - you rock ! :)

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