parent node link

Go to solution

Press Ctrl / CMD + C to copy this to your clipboard.

Copied to clipboard

Flag this post as spam?

This post will be reported to the moderators as potential spam to be looked at

Daniel Horn 319 posts 344 karma points

Mar 13, 2011 @ 13:52

I have this structure:

- News

-- 2011

--- news 1

--- news 2

-- 2010

--- news 4

--- news 5

-- 2009

On my frontpage I show both news from 2011 and 2010 - so how do i point them into the different pages (2011 and 2010).

So when you click on news 1 you go to the 2011 page and when you click on news 4 you go to the 2010 page?

It's my url3 i need to change to point to the parent of those news items.

Here's what i'm trying:

        <dl class="morenews">
           <dt><xsl:value-of select="$currentPage/ancestor-or-self::*[@isDoc]/flereNyhederOverskrift" /></dt>
          
            <xsl:for-each select="$currentPage/descendant-or-self::Nyhed [@isDoc]">
              <xsl:sort select="nyhedsdato" order="descending"/>
              <xsl:if test="position() &gt;3 and position() &lt;=6">
                <xsl:variable name="url3" select="$currentPage/parent::*[@isDoc]/nyhed"/>
                <xsl:variable name="url2" select="parent::node" />  
                
              <dd><a href="{$url3}#{@urlName}">
               <xsl:value-of select="titelLinie1"/></a></dd>
                  </xsl:if></xsl:for-each>
          
                   <dd class="allnews"><a>
                <xsl:if test="$url1 != ''">  
                <xsl:attribute name="href"><xsl:value-of select="umbraco.library:NiceUrl($url1)"/></xsl:attribute>
                </xsl:if><xsl:value-of select="$currentPage/ancestor-or-self::*[@isDoc]/lsFlereNyhederLinkTekst" /></a></dd>
               
                </dl>
      </div>

Copy Link

Kim Andersen 1447 posts 2196 karma points MVP

Mar 13, 2011 @ 14:13
1
Hi Daniel

If you want the $url3 to contain a link to the parent node try this:
```
<xsl:variable name="url3" select="umbraco.library:NiceUrl($currentPage/../@id)"/>
```
/Kim A
Copy Link
Jan Skovgaard 11280 posts 23678 karma points MVP 11x admin c-trib

Mar 13, 2011 @ 14:58

0

Hi Daniel

Perhpas you could also make sure that the link is always pointing to the second or third id in the @path attribute? (Or whatever place the id has in the path attribute).

This attributes contains a comma seperated list of nodeid's that makes up the path to the current node.

So by splitting the content of this attribute using umbraco.library:Split() you can always go to the correct id by writing something like...

<xsl:variable name="parent" select="umbraco.library:Split(@path,',')/values/value[2]" />

I hope this makes sense.

/Jan

Copy Link
Chriztian Steinmeier 2798 posts 8788 karma points MVP 8x admin c-trib

Mar 13, 2011 @ 22:59
2
Hi Daniel,

To get the url3 variable to point to the parent of the page you're currently at in the loop,

you should use current() instead of $currentPage - but in this case you can just ditch the

"$currentPage/" part. I *think* what you're aiming at is really something like Kim's suggestion,

but not using $currentPage - so effectively:
```
<xsl:variable name="url3" select="umbraco.library:NiceUrl(../@id)" />
```
@Jan: Don't mess with the @path attribute - it's usually much better to use the ancestor-or-self:: axis to access those nodes.

/Chriztian
Copy Link
Jan Skovgaard 11280 posts 23678 karma points MVP 11x admin c-trib

Mar 14, 2011 @ 07:25

0

Hi Chriztian

Yes of course - just meant as an alternative solution :-)

/Jan

Copy Link
Kim Andersen 1447 posts 2196 karma points MVP

Mar 14, 2011 @ 09:14

0

Holy smokes! How did I not notice that we where inside a loop :P

Yeah, of course you shouldn't use $currentPage then, but do like Chriztian says.

/Kim A

Copy Link
Daniel Horn 319 posts 344 karma points

Mar 14, 2011 @ 16:15

0

Thanks guys - you rock ! :)

Copy Link
is working on a reply...

Please Sign in or register to post replies