namespace problem youtube api - XSLT

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Inx51 54 posts 107 karma points

Mar 14, 2011 @ 12:30

0

Namespace problem? Youtube API

Hi!

Im trying to access some of the data from the youtube API by useing the following XSL

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp " "> ]>
<xsl:stylesheet
  version="1.0"
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  xmlns:msxml="urn:schemas-microsoft-com:xslt"
  xmlns:umbraco.library="urn:umbraco.library"
  xmlns:Exslt.ExsltCommon="urn:Exslt.ExsltCommon"
  xmlns:Exslt.ExsltDatesAndTimes="urn:Exslt.ExsltDatesAndTimes"
  xmlns:Exslt.ExsltMath="urn:Exslt.ExsltMath"
  xmlns:Exslt.ExsltRegularExpressions="urn:Exslt.ExsltRegularExpressions"
  xmlns:Exslt.ExsltStrings="urn:Exslt.ExsltStrings"
  xmlns:Exslt.ExsltSets="urn:Exslt.ExsltSets"
  xmlns:yt="gdata.youtube.com/feeds/api/videos/ADos_xW4_J0"
  exclude-result-prefixes="msxml umbraco.library Exslt.ExsltCommon Exslt.ExsltDatesAndTimes Exslt.ExsltMath Exslt.ExsltRegularExpressions Exslt.ExsltStrings Exslt.ExsltSets">

<xsl:output method="xml" omit-xml-declaration="yes"/>
<xsl:param name="currentPage"/>

<xsl:template match="/">
  
  <xsl:variable name="Feed" select="umbraco.library:GetXmlDocumentByUrl('http://gdata.youtube.com/feeds/api/videos/ADos_xW4_J0')" />

  <xsl:for-each select="$Feed/*[local-name()='entry']">
  <xsl:value-of select = "*[local-name()='yt:location']" disable-output-escaping="yes" />
  <hr/>
  </xsl:for-each>

</xsl:template>
</xsl:stylesheet>

The thing is that for some reason I can't get the value of yt:location..I whould guess its because of the namepsace..but Im not sure...so..anyway...how do I get the value of for instance in this case yt:location?

And by the way..any suggestions of improvments to this xslt-file is appreciated :)

Thanks in advance!

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Jeroen Breuer 4908 posts 12265 karma points MVP 5x admin c-trib

Mar 14, 2011 @ 12:58

0

Not sure if this will help, but you might want to have a look at uTube. It has some nice xslt samples: http://utube.codeplex.com/SourceControl/changeset/view/8325#196501

Jeroen

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Chriztian Steinmeier 2798 posts 8788 karma points MVP 8x admin c-trib

Mar 14, 2011 @ 13:37

Hi Inx51,

You've declared the namespace, so you should just be able to do:

<xsl:value-of select="yt:location" disable-output-escaping="yes" />

In fact - these should all work:

<xsl:value-of select="yt:location" disable-output-escaping="yes" />

<xsl:value-of select="*[name() = 'yt:location']" disable-output-escaping="yes" />

<xsl:value-of select="*[local-name() = 'location']" disable-output-escaping="yes" />

/Chriztian

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Inx51 54 posts 107 karma points

Mar 14, 2011 @ 13:38

0

Thanks :)..I did an ugly hack for it(atleast as I see it)..I simply added:

xmlns:yt="http://gdata.youtube.com/feeds/api/videos/ADos_xW4_J0"

To the

And then also added the prefix "yt" to the exclude-result-prefixes attribute :) and then used <xsl:value-of select = "*[local-name()='location']" disable-output-escaping="yes" />

:)

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Chriztian Steinmeier 2798 posts 8788 karma points MVP 8x admin c-trib

Mar 14, 2011 @ 20:32

0

What I was trying to tell you was that because you have declared the prefix (with xmlns:yt="...") you can (and should) use the full qualified name (yt:location) to access the element. It's that simple, and exactly how you do namespace stuff in XSLT.

/Chriztian

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Namespace problem? Youtube API