and if I get this right.. xslt cant use the following url:

gdata.youtube.com/feeds/api/channels?q=dog&v=2

since the & is causeing some problems..so is the thing that Im doing above even correct?

Have you tried URL encoding the the ampersand, e.g:

gdata.youtube.com/feeds/api/channels?q=dog&v=2

See if that does the trick!

If you still don't get any content when you have tried the suggestion of Tim could you please try to make a textarea in, which you write the content of your variable?

Like this:

<textarea>
<xsl:copy-of select="$utubexml" />
</textarea>

This should give you the XML structure, which should make it fairly easy to figure out how to match it.

/Jan

Hi Inx51,

It's the age-old gotcha of XML namespaces... you need to reference them explictally in your XSLT.

See here for an example: http://our.umbraco.org/forum/developers/xslt/8016-getXMLDocument-won't-display-any-content

I'll post an example XSLT if I have time.

Cheers, Lee.

... so, instead of going crazy with all those "local-name()" functions, lets look at doing it a better way.

Since the <feed> has an Atom namespace (xmlns), you'll need to reference that in your XSLT:

<xsl:stylesheet
    version="1.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:msxml="urn:schemas-microsoft-com:xslt"
    xmlns:atom="http://www.w3.org/2005/Atom"
    xmlns:umbraco.library="urn:umbraco.library"
    exclude-result-prefixes="msxml umbraco.library">

When you then grab the XML (by URL), you can use the "atom" namespace instead of the "local-name()" functions:

<xsl:variable name="utubexml" select="umbraco.library:GetXmlDocumentByUrl('http://gdata.youtube.com/feeds/api/channels?q=dog&amp;v=2')"/>
<xsl:for-each select="$utubexml/atom:feed/atom:entry">
    <xsl:value-of select="atom:title" disable-output-escaping="yes" />
    <hr/>
</xsl:for-each>

Namespaces can be confusing, trust me - I spend many hours/days bashing my head against a wall with this stuff!

Cheers, Lee.

is working on a reply...