problems with migrating xslt to new schema

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Eric Herlitz 97 posts 129 karma points

Mar 18, 2011 @ 17:01

I got this macro who's collecting articles (nodes) a hidden part of the site called "Article_archives". The articles are tagged with one or more categories (i.e 'baking, 'exercise', etc).

To get the articles I used to use the code below, and I cant figure out how to upgrade it to the new schema :(

<xsl:template match="/">

    <xsl:variable name="listcategory" select="umbraco.library:Split($currentPage/data[@alias='listcategory'],',')"/>
    <xsl:variable name="listname" select="@nodeName"/>

    <xsl:if test="$listcategory/value !=''">

    <xsl:for-each select="$currentPage/ancestor-or-self::node 
        [@level = 1]//node
        [umbraco.library:HasAccess(@id, @path) = true()]
        [umbraco.library:Split(data[@alias='Category'],',')/value = $listcategory/value]">

Any help is highly appreciated!

Cheers

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Ismail Mayat 4511 posts 10091 karma points MVP 2x admin c-trib

Mar 18, 2011 @ 17:08

1

Eic,

see http://our.umbraco.org/projects/developer-tools/xsltupdater-for-umbraco and http://our.umbraco.org/wiki/reference/xslt/45-xml-schema

Regards

Ismail

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Tom Fulton 2030 posts 4998 karma points c-trib

Mar 18, 2011 @ 17:08

Not tested, but try this: (just replaced /data [@alias='xx'] with /xx and /node with /* [@isDoc]

<xsl:template match="/">
        
        <xsl:variable name="listcategory" select="umbraco.library:Split($currentPage/listcategory,',')"/>
        <xsl:variable name="listname" select="@nodeName"/>
        
        <xsl:if test="$listcategory/value !=''">
        
        <xsl:for-each select="$currentPage/ancestor-or-self::* 
                [@isDoc][@level = 1]//*
    [@isDoc]
        [umbraco.library:HasAccess(@id, @path) = true()]
                [umbraco.library:Split(Category,',')/value = $listcategory/value]">

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Petr Snobelt 923 posts 1535 karma points

Mar 18, 2011 @ 17:10

<xsl:template match="/">
        
        <xsl:variable name="listcategory" select="umbraco.library:Split($currentPage/listcategory,',')"/>
        <xsl:variable name="listname" select="@nodeName"/>
        
        <xsl:if test="$listcategory/value !=''">
        
        <xsl:for-each select="$currentPage/ancestor-or-self::* [@isDoc][@level = 1]//* [@isDoc][umbraco.library:HasAccess(@id, @path) = true()]
                [umbraco.library:Split(Category,',')/value = $listcategory/value]">

converted by http://blackpoint.dk/umbraco-workbench/tools/convert-xml-schema-to-45-.aspx

Petr

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