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  • Biagio Paruolo 1618 posts 1910 karma points c-trib
    Mar 23, 2011 @ 17:32
    Biagio Paruolo
    0

    List Children of Child of one Node...How?

    How Do I loop on children of an hidden child of a node? That is:

    Content

      -- NodeA (it)

      ----  Hidden Node  (home)

      --------- Children1

      --------- Children2

      --------- Children3

     

    That is when I'm in NodeA, I wish children list of Hidden Node.

    I try with this

     <xsl:for-each select="$currentPage/ancestor-or-self::root/it/Home/*[@isDoc]">

    but nothing.

    Thanks

  • Chriztian Steinmeier 2800 posts 8790 karma points MVP 8x admin c-trib
    Mar 23, 2011 @ 22:57
    Chriztian Steinmeier
    0

    Hi Biagio,

    If $currentPage is "NodeA" and "Home" is the alias of the Document Type for the hidden node, you can very easily access the children of Home by doing this:

    <xsl:for-each select="$currentPage/Home/*[@isDoc]">
        <p><xsl:value-of select="@nodeName" /></p>
    </xsl:for-each>

    The fact that the node is hidden, is just a convention that if you use a property with the name umbracoNaviHide, the default XSLT "templates" (accessible in the Create XSLT file dialog) will skip nodes that have that property set. You can only truly hide a node from the XML by unpublishing it.

    /Chriztian

  • Biagio Paruolo 1618 posts 1910 karma points c-trib
    Mar 24, 2011 @ 10:47
    Biagio Paruolo
    0

    I try, but don't works...My script is:

    <xsl:value-of select="$currentPage/@nodeName"/>  --> this return "it" value
                  <ul class="tabbed">

                    <xsl:for-each select="$currentPage/Home/*[@isDoc]">
                       
                <li>
                  <xsl:if test="@id = current()/@id">
                    <xsl:attribute name="class">current-tab</xsl:attribute>
                  </xsl:if>
                  <a href="{umbraco.library:NiceUrl(@id)}">
                      <xsl:attribute name="id">nav-<xsl:value-of select="./umbracoUrlName"/></xsl:attribute>
                    <xsl:value-of select="@nodeName"/>
                  </a>

                </li>
              </xsl:for-each>
            </ul>

    I've empty list...

    It's not possible unpublish node because, after, I can not publish children.

  • Biagio Paruolo 1618 posts 1910 karma points c-trib
    Mar 26, 2011 @ 17:21
    Biagio Paruolo
    0

    I try this

    <xsl:for-each select="$currentPage/Home/*[@isDoc]">
            <p><xsl:value-of select="@nodeName" /></p>
    </xsl:for-each>

    and I've tested that I'm in node "it" with <xsl:value-of select="$currentPage/@nodeName"/> ,but "for-each" ( see up ) return empty value..

     

     

  • Chriztian Steinmeier 2800 posts 8790 karma points MVP 8x admin c-trib
    Mar 26, 2011 @ 21:27
    Chriztian Steinmeier
    1

    Hi Biagio,

    That simply means that "Home" is not the name/alias of the hidden Document Type - it's a case-sensitive name, maybe it's "home" ?

    You can also reference it by @nodeName - e.g., if it's called 'Home' in the Content Tree you'd do this:

    <xsl:for-each select="$currentPage/*[@nodeName = 'Home']/*[@isDoc]">

    /Chriztian

     

  • Biagio Paruolo 1618 posts 1910 karma points c-trib
    Mar 27, 2011 @ 13:05
    Biagio Paruolo
    0

    This work...Thanks

    <xsl:for-each select="$currentPage/*[@nodeName = 'Home']/*[@isDoc]">
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