check if node has child nodes

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vaibhav 119 posts 139 karma points

Mar 25, 2011 @ 07:55

XSLT

Hello all

I want o check if node has child nodes or not ...i tried but not getting

Here is my code...

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp "&#x00A0;"> ]>
<xsl:stylesheet 
  version="1.0" 
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
  xmlns:msxml="urn:schemas-microsoft-com:xslt" 
  xmlns:umbraco.library="urn:umbraco.library" xmlns:Exslt.ExsltCommon="urn:Exslt.ExsltCommon" xmlns:Exslt.ExsltDatesAndTimes="urn:Exslt.ExsltDatesAndTimes" xmlns:Exslt.ExsltMath="urn:Exslt.ExsltMath" xmlns:Exslt.ExsltRegularExpressions="urn:Exslt.ExsltRegularExpressions" xmlns:Exslt.ExsltStrings="urn:Exslt.ExsltStrings" xmlns:Exslt.ExsltSets="urn:Exslt.ExsltSets" xmlns:tagsLib="urn:tagsLib" xmlns:BlogLibrary="urn:BlogLibrary" 
  exclude-result-prefixes="msxml
 umbraco.library Exslt.ExsltCommon Exslt.ExsltDatesAndTimes 
Exslt.ExsltMath Exslt.ExsltRegularExpressions Exslt.ExsltStrings 
Exslt.ExsltSets tagsLib BlogLibrary ">

<xsl:output method="xml" omit-xml-declaration="yes"/>

<xsl:param name="currentPage"/>

<xsl:template match="/">

<!-- The fun starts here -->
<xsl:if test="count(./node) &gt; 0">    <!-- checking for child nodes  -->
 Select <xsl:value-of select="$currentPage/@nodeName"/> :  
   <ul>
    <xsl:for-each select="$currentPage/* [@isDoc and string(umbracoNaviHide) != '1']">
      <li>
        <a href="{umbraco.library:NiceUrl(@id)}">
        <xsl:value-of select="@nodeName"/>
        </a>
      </li>
    </xsl:for-each>
   </ul>
  </xsl:if>
</xsl:template>

</xsl:stylesheet>

I am making some mistak ..plz solvei t ...

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Pasang Tamang 258 posts 458 karma points

Mar 25, 2011 @ 08:06

Hi,

To check the child node you have to check counting of the child nodes. Here is sample code

<xsl:for-each select="$currentPage/* [@isDoc and string(umbracoNaviHide) != '1']">
 <xsl:variable name="child" select="umbraco.library:GetXmlNodeById(@id)/*[@isDoc]"/>
        <xsl:if test="count($child) > 0">
         <xsl:value-of select="@nodeName"/>
        </xsl:if>
</xsl:for-each>

Hope this helps

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Daniel Bardi 927 posts 2562 karma points

Mar 25, 2011 @ 08:19
0
```
<xsl:if test="count($currentPage/*) &gt; 0">

... do something ...

</xsl:if>
```
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Kishore kumar Kandavalli 2 posts 71 karma points

Oct 18, 2018 @ 15:40

0

hi daniel, can you please tell me how to display the count the nodes and its descendent nodes from xslt to html output. can you please tell me how to solve this ? thanks in advance

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vaibhav 119 posts 139 karma points

Mar 25, 2011 @ 08:26

0

@ Pasang ..... i want to check whether current node has child node & if yes then it will go into for-each loop ....

@Daniel .....I used that if statement but it is showing text even if there is no child node .....

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Daniel Bardi 927 posts 2562 karma points

Mar 25, 2011 @ 08:27
0
```
<xsl:if test="count($currentPage/self::*[@isDoc]) &gt; 0">

... do something ...

</xsl:if>
```
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vaibhav 119 posts 139 karma points

Mar 25, 2011 @ 08:45
0
I made some change to ur if statement Daniel & then it worked....
```
<xsl:if test="$currentPage/* [@isDoc and string(umbracoNaviHide) != '0']">

</xsl:if>
```
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Daniel Bardi 927 posts 2562 karma points

Mar 25, 2011 @ 08:48

0

that looks great... very late here in the US.. my brain is mush..

Great job!

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Dmitrij Jazel 86 posts 179 karma points

Jun 22, 2012 @ 09:13

Hi guys,

I actually just tryed to achieve the same here (check if current node I am iterating on has any children) and Vaibhavs suggestion just worked for me.

<xsl:if test="current()/* [@isDoc and string(umbracoNaviHide) != '1']">    <!-- checking for child nodes  -->
              <ul id="list-content">
                <xsl:for-each select="current()/child::* [@isDoc and string(umbracoNaviHide) != '1']">
                  <li>
                    <a href="{umbraco.library:NiceUrl(@id)}" class="M2">
                      <xsl:value-of select="@nodeName"/>
                    </a>                      
                  </li>
                </xsl:for-each> 
              </ul>
    </xsl:if>

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Steve 472 posts 1216 karma points

Aug 28, 2012 @ 17:19

0

I have a similar need, but I need to check only the top level parents in a <ul> to see if they have children and if they don't apply a <href>. All subsuquent children should allways have a link applied to them though. Any ideas?

Page I am woring with:

https://edit-www.rose-hulman.edu/offices-services/alumni-affairs-2.aspx

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nesttor 4 posts 24 karma points

Nov 13, 2012 @ 06:18

0

Thanks Dmitrij for your code,, it worked for me :)

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Devin Bost 37 posts 78 karma points c-trib

Jan 19, 2014 @ 23:05

Here's an example of using this in a hierarchical list:

<ul class="navClearLevel1Ul">
<xsl:for-each select="$currentPage/ancestor-or-self::* [@level=$level]/* [@isDoc and string(umbracoNaviHide) != '1']">
<li class="navClearLevel1Li">
    <a href="{umbraco.library:NiceUrl(@id)}">
        <xsl:value-of select="@nodeName"/>
    </a>
    <xsl:variable name="child" select="umbraco.library:GetXmlNodeById(@id)/*[@isDoc]"/>
    <xsl:if test="count($child) &gt; 0">
    <ul class="navClearLevel2Ul">
        <xsl:for-each select="@nodeName/ancestor-or-self::* [@level=$level2]/* [@isDoc and string(umbracoNaviHide) != '1']">
        <li class="navClearLevel2Li">
            <a href="{umbraco.library:NiceUrl(@id)}">
                <xsl:value-of select="@nodeName"/>
            </a>
        </li>
        </xsl:for-each>
    </ul>
    </xsl:if>
</li>
</xsl:for-each>
</ul>

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